Answer:
Input:
x/x + 1 - 1/x - 1 + 2×x/x^2 - 1
Result:
1/x
<span> binomdist with n = 3, p = 0.82, q = 1-0.82 = 0.18
P[≥2] = P[2] + P[3] = 3c2 *0.82^2*0.18 + 0.82^3 ≈ 91%
hope it helps
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The function is definately defined at x=0 but not x=1.
But its just one part of the coordinate (x,y).
If the value of y or f(x) is considered, you'll see that it is never possible to attain f(x)=0. In other terms (x,y)= (0,0) is not a defined point in the graph of the function because the graph doesnt pass through that point.
Now I hope you understood what I meant!
Conclusion- The above function is not defined at all points in the space having the abscissa or x=1 in the coordinate and also at ordinate or y=0 in the coordinate.nation:
Answer:
The LCD in 1/30 + 1/24 is <u>90</u>.
Answer:
yes
Step-by-step explanation:
