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german
2 years ago
5

He temperature moreased by 8' Fahrenheit

Mathematics
1 answer:
kompoz [17]2 years ago
6 0

it is B The temperature started at 78°F and increased by 6°F Then the temperature increased by 5°F

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How do you subtract 7.6 from 20.39
larisa [96]
20.39 -7.6 = 12.79
8 0
3 years ago
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Find the sum of the first 9 terms of the sequence. Show all work for full credit.
Kamila [148]
We can see the sequence goes by decreasing 9 on each number

so the numbers are

2, -7, -16, -25, -34, -43, -52, -61, -70

so adding all these numbers we get

2-7-16-25-34-43-52-61-70

= -306


hope this helped
6 0
3 years ago
the length of a rectangle is five feet less than its width. If the area of the rectangle is 84 square feet, find its dimensions
KIM [24]
Let
x---------> the length of the rectangle
y--------> the width of the rectangle

we know that
A=84 ft²
[area of rectangle]=x*y-----> 84=x*y-----> equation 1
x=y-5------> equation 2
substitute 2 in 1
84=[y-5]*y-----> 84=y²-5y---------> y²-5y-84=0

using a graph tool-----> to resolve the second order equation
see the attached figure

the solution is
y=12
x=y-5-----> x=12-5-----> x=7

the answer is
the length of the rectangle is 7 ft
the width of the rectangle is 12 ft

6 0
3 years ago
Find the distance between the two points in simplest radical form <br> (4,6) and (-2,9)
MrRa [10]

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{4}~,~\stackrel{y_1}{6})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{9})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d = \sqrt{(-2-4)^2+(9-6)^2}\implies d = \sqrt{(-6)^2+3^2}\implies d = \sqrt{36+9} \\\\\\ d = \sqrt{45}\implies d = \sqrt{9\cdot 5}\implies d=\sqrt{3^2\cdot 5}\implies d = 3\sqrt{5}

6 0
3 years ago
What is the slope–intercept form of the equation 4x − 2y = 9?
adelina 88 [10]
Hey there! :D

Slope intercept form: y=mx+b

4x-2y=9

Add 2y to the other side. 

4x=9+2y

Subtract 9 on both sides.

4x-9=2y

Flip the equation over. 

2y=4x-9 <== slope intercept form 

I hope this helps!
~kaikers
5 0
3 years ago
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