He temperature moreased by 8' Fahrenheit

(02.06)A local store has a puppy that weighs 56 ounces. How many pounds does the puppy weigh, given that 1 pound = 16 ounces? (I

viktelen [127]

The answer should be 3.5 pounds. You divide 56 by 16 to get your answer

3 0

3 years ago

4. Diego is thinking of two positive numbers. He says, "If we triple the first number and

aleksandr82 [10.1K]

Answer:

3x + 2y = 34. and two possible pairs of positive numbers are (x, y) = (10, 2) and (x, y) = (4, 11).

Step-by-step explanation:

Let the First positive number be x and second positive number be y.

Triple of first number = 3x

double of second number = 2y

According to question,

3x + 2y = 34

Therefore, the equation is 3x + 2y = 34

So the two possible pair of numbers Diego would be thinking of must satisfy the equation 3x + 2y = 34

Now, 3x + 2y = 34

3x = 34 - 2y

Let x = 10 and by substituting its value in above expression,

$3 \times 10 = 34 - 2y$

$30 = 34 - 2y$

$2y = 34 - 30$

$2y = 4$

$y = 2$

Therefore first pair (x, y) = (10, 2)

In the same way put x = 4 then,

3x = 34 - 2y

$3 \times 4 = 34 - 2y$

$2y = 34 - 12$

$2y = 22$

$y = 11$

Therefore first pair (x, y) = (4, 11)

Therefore, (x, y) = (4, 11) and (x, y) = (10, 2) are the two possible pairs of numbers Diego could be thinking of as these both values satisfy the equation 3x + 2y = 34.

8 0

2 years ago

Which of these sets could represent the side lengths of a right triangle?

Jlenok [28]

Answer:

{6, 8, 10} is a set which represents the side length of a right triangle.

Step-by-step explanation:

In a right triangle:

$(Base)^{2} + (Perpendicular)^{2} = (Hypotenuse)^{2}$

Now, in the given triplets:

(a) {4, 8, 12}

Here, $(4)^{2} + (8)^{2} = 16 + 64 = 80\\\implies H = \sqrt{80} = 8.94$

So, third side of the triangle 8.94 ≠ 12

Hence, {4, 8, 12} is NOT a triplet.

(b) {6, 8, 10}

Here, $(6)^{2} + (8)^{2} = 36 + 64 = 100\\\implies H = \sqrt{100} = 10$

So, third side of the triangle 10

Hence, {6, 8, 10} is a triplet.

(c) {6, 8, 15}

Here, $(6)^{2} + (8)^{2} = 36 + 64 = 100\\\implies H = \sqrt{100} = 10$

So, third side of the triangle 10 ≠ 15

Hence, {6, 8, 15} is NOT a triplet.

(d) {5, 7, 13}

Here, $(5)^{2} + (7)^{2} = 25 + 49 = 74\\\implies H = \sqrt{74} = 8.60$

So, third side of the triangle 8.60 ≠ 13

Hence, {5, 7, 13} is NOT a triplet.

4 0

3 years ago

The larger of two numbers is 15 more than 3 times the smaller number. If the sum of the two numbers is 63 find the numbers

scoray [572]

Answer:

X = 51

Y = 12

Step-by-step explanation:

2 numbers: (Larger) Number 1 is x and Number 2 is y

The equation is x + y = 63

x = 3y +15
y = y

New equation is:

3y + 15 + y = 63

Combine like variables:

4y + 15 = 63

Solve:

4y + 15 - 15 = 63 - 15
4y = 48

Divide 4 from each side:

y = 12

To find x fill in the variables from the 'x =' equation:

x = 3y + 15
x = 3( 12) + 15
x = 51

3 0

3 years ago

Plzzz help plzzzzzzzzzzzzzz

mezya [45]

Given:

The figure of two quadrilaterals.

In $ABCD,AB=18,BC=20,CD=22,AD=24$

In $EFGH,EF=27,FG=30,GH=34, EH=36$

To find:

Whether the figures are congruent, similar or neither.

Solution:

Ratio of corresponding sides are:

$\dfrac{AB}{EF}=\dfrac{18}{27}$

$\dfrac{AB}{EF}=\dfrac{2}{3}$

Similarly,

$\dfrac{BC}{FG}=\dfrac{20}{30}$

$\dfrac{BC}{FG}=\dfrac{2}{3}$

$\dfrac{CD}{GH}=\dfrac{22}{34}$

$\dfrac{CD}{GH}=\dfrac{11}{17}$

And,

$\dfrac{AD}{EH}=\dfrac{24}{36}$

$\dfrac{AD}{EH}=\dfrac{2}{3}$

Clearly, $\dfrac{AB}{EF}=\dfrac{BC}{FG}=\dfrac{AD}{EH}\neq \dfrac{CD}{GH}$ .

All corresponding sides are not proportional.

Therefore, the figures are neither similar nor congruent. Hence, third option is correct.

7 0

2 years ago