DE = AB, EF = BC and AC = DF, hence triangle ABC is congruent to triangle DEF.
<h3>
Congruent shape</h3>
Two shapes are said to be congruent if they have the same shape, all their corresponding angles and sides are congruent to one another.
Given that DE = AB and BC = EF.
In right triangle DEF, using Pythagoras:
DF² = DE² + EF²
Also, In right triangle ABC, using Pythagoras:
AC² = AB² + BC²
But DE = AB and EF = BC, hence:
AC² = DE² + EF²
AC² = DF²
Taking square root of both sides, hence:
AC = DF
Since DE = AB, EF = BC and AC = DF, hence triangle ABC is congruent to triangle DEF.
Find out more on Congruent shape at: brainly.com/question/11329400
Answer:
B . tell me if ya need proof
Step-by-step explanation:
Answer:
5
Step-by-step explanation:
$4.75 + 0.3x = $6.26
0.3x = 1.51
x = 5.033
Answer: One sample z test for means
Step-by-step explanation:
From the information given, the sample size is large. It is greater than 30. Again, the population standard deviation is given. This means that the test statistic would be the z score which is determined by the formula
z = (x - µ)/σ
Where
x = sample mean
µ = population mean
σ = population standard deviation
The probability value would be determined from the normal distribution table.
Therefore, the hypothesis test that should be used is
One sample z test for means
X=6 and y=-9. Not sure if y is correct since I kind of rushed but I hope this helps!
