If the area of a rectangle = LxW
Your answer would be (5y-6) (2y+10)
The answer is c in decimal it would be <span>1.87500
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Answer: Length = 10cm
Width = 6.5cm
Step-by-step explanation:
Let the width of the rectangle be represented by x.
Therefore, the length of the rectangle will be: = (2 × x) - 3 = 2x - 3
Therefore area of a rectangle = length × width
x(2x - 3) = 65
2x² - 3x = 65
2x² - 3x - 65 = 0
2x² + 10x - 13x - 65 = 0
2x(x + 5) - 13(x + 5) = 0
(2x - 13)(x + 5) = 0
2x - 13 = 0
2x = 13
x = 13/2
x = 6.5
Width = 6.5cm
Length = 2x - 3
= 2(6.5) - 3
= 13 - 3
= 10cm
Therefore, the length of the rectangle is 10cm and the width is 6.5cm.
Answer:
The width of the field is 4x + 20 / x² -2x -3 yards
Step-by-step explanation:
The area of a rectangular field is given by the following formula:
area = length*width
In this case we want to find the width of this field, therefore if we isolate the width in the expression above we will have a suitable expression:
width*length = area
width = area / length
So applying the data from the problem, we have:
width = [(2x + 6)/(x + 1)] / [(x² - 9)/(2x + 10)]
width = [(2x + 6)/(x + 1)]*[(2x + 10)/(x² - 9)]
width = 2(x + 3)*(2x + 10) / (x+1)*(x - 3)*(x + 3)
width = 2*(2x + 10) / (x + 1)*(x - 3)
width = 4x + 20 / x² -2x -3