Answer:
Mean track length for this rock specimen is between 10.463 and 13.537
Step-by-step explanation:
99% confidence interval for the mean track length for rock specimen can be calculated using the formula:
M±
where
- M is the average track length (12 μm) in the report
- t is the two tailed t-score in 99% confidence interval (2.977)
- s is the standard deviation of track lengths in the report (2 μm)
- N is the total number of tracks (15)
putting these numbers in the formula, we get confidence interval in 99% confidence as:
12±
=12±1.537
Therefore, mean track length for this rock specimen is between 10.463 and 13.537
Answer:
-2j - 6
Step-by-step explanation:
3j - 2 + (-5j) - 4
3j - 2 - 5j - 4
<em><u>-2j - 6</u></em>
Answer: 2^2 x 3^2 x 5
You can use a star symbol * in place of the x symbols.
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Explanation:
We simply circle the primes where they have the largest exponent.
The unique primes listed here are: 2, 3, 5
- The prime 2 has the highest exponent of 2, meaning 2^2 is part of the answer.
- The prime 3 has the highest exponent of 2, meaning 3^2 is also part of the LCM
- The prime 5, without any exponent, is also part of the LCM. We can write this as 5^1 or just leave it as 5.
.05s + s
S is the price of the shoes.
.05 = 5% so .05 times the original price, s, is tax which you add on to the actual price.
108 below ground is -108 because 0 is ground level
