make a conjecture (prediction) about the table. what will happen if we continue the table, going down?

What is the measure of DG?

Masja [62]

Answer:

170

Step-by-step explanation:

7 0

2 years ago

You throw a stone with a force of 55.1 N. It accelerates at 41.6 m/s2.

Mice21 [21]

Answer:

Mass = 1.3 Kilograms.

Step-by-step explanation:

Given the following data;

Force = 55.1 N

Acceleration = 41.6 m/s²

To find the mass of the stone in kg;

Newton's Second Law of Motion states that the acceleration of a physical object is directly proportional to the net force acting on the physical object and inversely proportional to its mass.

Mathematically, it is given by the formula;

Force = mass * acceleration

Substituting into the formula, we have;

55.1 = mass * 41.6

$Mass = \frac {55.1}{41.6}$

Mass = 1.3 Kilograms

6 0

2 years ago

What number would go in the blank? (3 • 5) • 2 = 3 • (__ • 2) 10 5 2

tester [92]

Answer:

5

Step-by-step explanation:

It's the one that's missing.

Hope I helped!

Please mark Brainliest!

7 0

2 years ago

Read 2 more answers

There are 60 treats. he is allowed 2 treats a day. how many treats will he have left after 10 days?

nydimaria [60]

2 x 10=20 60-20=40. 40 treats left

6 0

3 years ago

(a) Use the power series expansions for ex, sin x, cos x, and geometric series to find the first three nonzero terms in the powe

Fofino [41]

Answer:

a) $\mathbf{4 + \dfrac{x}{1!}- \dfrac{2x^2}{2!} ...}$

b) See Below for proper explanation

Step-by-step explanation:

a) The objective here is to Use the power series expansions for ex, sin x, cos x, and geometric series to find the first three nonzero terms in the power series expansion of the given function.

The function is $e^x + 3 \ cos \ x$

The expansion is of $e^x$ is $e^x = 1 + \dfrac{x}{1!}+ \dfrac{x^2}{2!}+ \dfrac{x^3}{3!} + ...$

The expansion of cos x is $cos \ x = 1 - \dfrac{x^2}{2!}+ \dfrac{x^4}{4!}- \dfrac{x^6}{6!}+ ...$

Therefore; $e^x + 3 \ cos \ x = 1 + \dfrac{x}{1!}+ \dfrac{x^2}{2!}+ \dfrac{x^3}{3!} + ... 3[1 - \dfrac{x^2}{2!}+ \dfrac{x^4}{4!}- \dfrac{x^6}{6!}+ ...]$

$e^x + 3 \ cos \ x = 4 + \dfrac{x}{1!}- \dfrac{2x^2}{2!} + \dfrac{x^3}{3!}+ ...$

Thus, the first three terms of the above series are:

$\mathbf{4 + \dfrac{x}{1!}- \dfrac{2x^2}{2!} ...}$

b)

The series for $e^x + 3 \ cos \ x$ is $\sum \limits^{\infty}_{x=0} \dfrac{x^x}{n!} + 3 \sum \limits^{\infty}_{x=0} ( -1 )^x \dfrac{x^{2x}}{(2n)!}$

let consider the series; $\sum \limits^{\infty}_{x=0} \dfrac{x^x}{n!}$

$|\frac{a_x+1}{a_x}| = | \frac{x^{n+1}}{(n+1)!} * \frac{n!}{x^x}| = |\frac{x}{(n+1)}| \to 0 \ as \ n \to \infty$

Thus it converges for all value of x

Let also consider the series $\sum \limits^{\infty}_{x=0}(-1)^x\dfrac{x^{2n}}{(2n)!}$

It also converges for all values of x

7 0

3 years ago

make a conjecture (prediction) about the table. what will happen if we continue the table, going down? ​

make a conjecture (prediction) about the table. what will happen if we continue the table, going down?