Answer:
I think answer is B or C or D
Step-by-step explanation:
Answer:
8b + 6x + 5x + 18
Step-by-step explanation:
8b + 7 + 6x + 4 + 5c + 8
8b + 6x + 5x + 18
Answer: 8b + 6x + 5x + 18
13.) A=9cm^2
If the area is l•h, and there are 9 cubic squares, that means that the length of each side on the square is 3cm, each square on it equals 1cm.
14.) V=27cm^3
If the volume is l•w•h, then we find the third power square root of 27, so 3•3=9•3=27, the answer is 3cm for the length, width, and height.
15.) V=4,913cm^3
If volume is l•w•h, then what number when raised to the third power equals 4913? The answer is 17, since 17•17=289•17=4913. So the length is 17cm
16.)V=216cm^3
If volume is l•w•h, then what number when raised to the third power equals 216? The answer is 6, since 6•6=36•6=216.
17.)A=121
Is area is l•w, then what number raised to the second power equals 121? The answer is 11, since 11•11=121. Therefore it WILL NOT fit a car with a length of 13ft.
18.)A=141
If area is l•w, then what number raised to the second power equals 141? The answer is 12, since 11.87•11.87=141 (answer was rounded to nearest whole number) meaning that she will need 12ft of fence to enclose her garden.
Answer:
25
Step-by-step explanation:
Given that:
A large circle in the park has its middle part painted.
The circle is divided in 4 equal parts.
Radius of the circle = 10 meters
To find:
Area of each section of the circle,
= ?
Solution:
Here, we need to find the area of the bigger circle first and then need to divide it into 4 equal parts to find out the answer.
First of all, let us have a look at the formula for area of a circle with given radius
:

Here, 
Putting the value in the above formula, we get:
So, area = 
Now, there are 4 equal parts of the circle, therefore area of each section will be equal.
Area of each section of the circle:

I've attached an image showing the coordinates of Ship A and Ship B.
Answer:
distressed vessel is located at (1, 1.5)
Step-by-step explanation:
From the image attached, we can see that;
Coordinate of ship A is (3, 4)
Coordinate of ship B is (1, 1)
Now, we are told that Ship A receives a distress signal from the southwest, and ship B receives a distress from the same vessel from the north.
This means that the distressed ship is somewhere in between ship A & B.
To solve this, we will extend the arrow line from Ship A in that same SW direction and we will do the same for ship B in the same North direction. Their point of intersection is where the distressed ship is located.
Now, if we do that, we will see that they will intersect at the point; (1, 1.5)
Thus,distressed vessel is located at (1, 1.5)