Answer:
Step-by-step explanation:
i am unsure of what you actually need, but i want to help you.
if you were to set the boundaries of the feasibility region it would be as follows:
as points
A(1, 17/3) B(7, 11/3) C(7, infinity) D(1, infinity)
as graphs
y=-1/3x+6 where 1≤x≤7
x=1
x=7
Formula for mid point.
(x1/2+x2/2 , y1/2+ y2/2)
Mid point=
(1/2+ (-3)/2 , 4/2+ 7/2)
(-2/2 , 11/2)
(-1, 5.5)
Answer:
Note that the tangents to the circles at A and B intersect at a point Z on XY by radical center. Then, since∠ZAB=∠ZQA and ∠ZBA=∠ZQB. ∠AZB+∠AQB=∠AZB+∠ZAB+∠ZBA=180°. ∴ZAQB is cyclic.But if O is the center of w, clearly ZAOB is cyclic with diameter ZO, so ∠ZQO is 90° ⇒Q is the mid-point of XY.Then, by Power of a Point, PY· PX = PA · PB = 15 and it is given that PY+PX = 11. Thus,PX=(11±
)/2. So, PQ=
, PQ²=
. Thus, the answer is 61+4=65.
Step-by-step explanation:
Answer:
ans x=4
Step-by-step explanation:
- 5x + 7 = -13
- 5x = -13 -7
- 5x= -20
- x = -20/5
- x = -4
- so the answer is x= -4