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Andrei [34K]
2 years ago
10

Points!!!!!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
Sholpan [36]2 years ago
6 0

Answer:

THANKS!!!!!!!!!

Step-by-step explanation:

lianna [129]2 years ago
5 0

Answer:

Hello! The answer for ur question is unavailable

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7/5=x/3 solve proportion
-BARSIC- [3]
Cross-multiply: 7 * 3 = 5 * x Divide each side by 5 : X = 7 * 3 / 5 = 4.2
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Moshe has the container shown below on his desk to hold pencils and paper clips. 2 rectangular prisms. One has a length of 4 inc
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2 inches by 3 inches by 6 inches and 2 inches by 2 inches by 4 inches

Step-by-step explanation:

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What is the common difference of the arithmetic sequence graphed below?
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Option D 2 is correct...hope it helps:)

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2 years ago
Could someone answer these 3 for me?
KengaRu [80]

Answer:

x=4.77

Angle 3=98.32 degrees

Angle 6= 81.68 degrees

Step-by-step explanation:

(Assuming these are parallel lines), Angle 3 and angle 5 are equal because they are alternate Angles. Therefore we can write the following equation to solves for x:

16x+22=3x+84 (angle 3=angle5)

Which we can now solve:

16x +22 - 22 - 3x=3x-3x+84-22

13x=62

13x/13=62/13

x=4.77 (2dp)

We can then use this x to calculate angle 3:

16(4.77)+22

76.33+22=98.32 degrees

Finally,

Angle 6 and angle 3 are interior angles, so they add up to 180 degrees.

So to find angle 6,we can just subtract angle 3 from 180:

180-98.32=81.68 degrees.

Hope this helped!

6 0
3 years ago
Does the point (-4, 2) lie inside or outside or on the circle x^2 + y^2 = 25?​
stiv31 [10]

Given equation of the Circle is ,

\sf\implies x^2 + y^2 = 25

And we need to tell that whether the point (-4,2) lies inside or outside the circle. On converting the equation into Standard form and determinimg the centre of the circle as ,

\sf\implies (x-0)^2 +( y-0)^2 = 5 ^2

Here we can say that ,

• <u>Radius</u> = 5 units

• <u>Centre </u> = (0,0)

<u>Finding</u><u> </u><u>distance</u><u> between</u><u> </u><u>the </u><u>two </u><u>points</u><u> </u><u>:</u><u>-</u><u> </u>

\sf\implies Distance = \sqrt{ (0+4)^2+(2-0)^2} \\\\\sf\implies Distance = \sqrt{ 16 + 4 } \\\\\sf\implies Distance =\sqrt{20}\\\\\sf\implies\red{ Distance = 4.47 }

  • Here we can see that the distance of point from centre is less than the radius.

<u>Hence </u><u>the</u><u> </u><u>point</u><u> </u><u>lies </u><u>within</u><u> </u><u>the </u><u>circle</u><u> </u><u>.</u>

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3 years ago
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