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Marat540 [252]
3 years ago
15

Shawndra said that it is not possible to draw a trapezoid that is a rectangle, but it is possible to draw a square that is a rec

tangle. Marcella said that it is possible. Who is correct? Explain your answer using the properties of quadrilaterals.
Mathematics
2 answers:
Gemiola [76]3 years ago
5 0
Marcella is correct for this problem

maks197457 [2]3 years ago
4 0

Solution :

Shawndra said that it is not possible to draw a trapezoid that is a rectangle, but it is possible to draw a square that is a rectangle.

The bases of the trapezoid are parallel to each other but the sides,angles and diagonals of the trapezoid are not congruent . While the opposite sides, angles and the diagonals of  the rectangle are congruent .Therefore , it is not possible to draw a trapezoid that is a rectangle.

A square is a parallelogram whose  opposite sides are parallel and congruent, all angles are right. These properties are also found in a rectangle. Therefore,  it is possible to draw a square that is a rectangle.

Hence, Shawndra is saying correct.

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The system of equations relates the distance, y,
Monica [59]
Is it 7.1 or something I don’t know for sure
8 0
3 years ago
Which statement best reflects the solution(s) of the equation?
Inessa [10]

x=2 is only solution while x=1 is extraneous solution

Option C is correct.

Step-by-step explanation:

We need to solve the equation \frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1} and find values of x.

Solving:

Find the LCM of denominators x-1,x and x-1. The LCM is x(x-1)

Multiply the entire equation with x(x-1)

\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}\\\frac{1}{x-1}*x(x-1)+\frac{2}{x}*x(x-1)=\frac{x}{x-1}*x(x-1)\\Cancelling\,\,out\,\,the\,\,same\,\,terms:\\x+2(x-1)=x^2\\x+2x-2=x^2\\3x-2=x^2\\x^2-3x+2=0

Now, factoring the term:

x^2-2x-x+2=0\\x(x-2)-1(x-2)=0\\(x-1)(x-2)=0\\x-1=0\,\,and\,\, x-2=0\\x=1\,\,and\,\, x=2

The values of x are x=1 and x=2

Checking for extraneous roots:

Extraneous roots: The root that is the solution of the equation but when we put it in the equation the answer turns out not to be right.

If we put x=1 in the equation, \frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}  the denominator becomes zero i.e

\frac{1}{1-1}+\frac{2}{1}=\frac{1}{1-1}\\\frac{1}{0}+2=\frac{1}{0}

which is not correct as in fraction anything divided by zero is undefined. So, x=1 is an extraneous solution.

If we put x=2  in the equation,

\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}

\frac{1}{2-1}+\frac{2}{2}=\frac{2}{2-1}\\\frac{1}{1}+1=\frac{2}{1}\\1+1=2\\2=2

So, x=2 is only solution while x=1 is extraneous solution

Option C is correct.

Keywords: Solving Equations and checking extraneous solution

Learn more about Solving Equations and checking extraneous solution at:

  • brainly.com/question/1626495
  • brainly.com/question/2959656
  • brainly.com/question/2456302

#learnwithBrainly

5 0
4 years ago
The expression for the distance traveled is rt where r represents rate and t represents time.
astraxan [27]

I don't really get what the "35,000 feet university sea level" part is saying, but without it, the answer would be:

3.5 x 550 = 1,925

The plane traveled 1,925 miles.

And with it, the answer would be:

3.5 x 550 = 1,925

35,000 ft = 6.6 mi

1,925 + 6.6 = 1,931.6

The plane traveled 1,931.6 miles.

Hope this helped a little at least.

8 0
3 years ago
Help me solve this.<br>​
almond37 [142]

Answer:

thx-step explanation:

6 0
3 years ago
Trapezoid ABCD is congruent to trapezoid . Which sequence of transformations could have been used to transform trapezoid ABCD to
dedylja [7]
The answer is D: Trapezoid ABCD was reflected across the y-axis and then rotated 90° counterclockwise around the origin
4 0
3 years ago
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