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Marat540 [252]
3 years ago
15

Shawndra said that it is not possible to draw a trapezoid that is a rectangle, but it is possible to draw a square that is a rec

tangle. Marcella said that it is possible. Who is correct? Explain your answer using the properties of quadrilaterals.
Mathematics
2 answers:
Gemiola [76]3 years ago
5 0
Marcella is correct for this problem

maks197457 [2]3 years ago
4 0

Solution :

Shawndra said that it is not possible to draw a trapezoid that is a rectangle, but it is possible to draw a square that is a rectangle.

The bases of the trapezoid are parallel to each other but the sides,angles and diagonals of the trapezoid are not congruent . While the opposite sides, angles and the diagonals of  the rectangle are congruent .Therefore , it is not possible to draw a trapezoid that is a rectangle.

A square is a parallelogram whose  opposite sides are parallel and congruent, all angles are right. These properties are also found in a rectangle. Therefore,  it is possible to draw a square that is a rectangle.

Hence, Shawndra is saying correct.

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Is -4 a solution for the equation 5x (2-4)=2(5x -4)?
yarga [219]

Answer:

no it is 0.4

Step-by-step explanation:

5x(2-4)=2(5x-4)

10x-20x=10x-8

-20x=-8

20x=8

10x=4

x=0.4

8 0
3 years ago
Plz help! Due tonight!
Alecsey [184]

the answer will be

48$ dollars

7 0
3 years ago
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According to the box-and-whisker plot shown above, what are the following:
Readme [11.4K]

Answer:

  6.  80

  7.  60

  8.  100

  9.  40

  10.  110

Step-by-step explanation:

A box and whisker plot is a visual representation of the 5-number summary of a data set. The features of the plot are, left-to-right, the minimum, first quartile, median, third quartile, maximum.

You are being asked to identify the numerical value associated with each of these features.

__

The left whisker extends to the minimum of 40.

The left end of the box identifies the first quartile as 60.

The line in the middle of the box is the median, 80.

The right end of the box identifies the third quartile as 100.

The right whisker extends to the maximum of 110.

__

<em>Additional comment</em>

We hope you can rearrange the order of these numbers to suit the order in which the questions ask for them.

4 0
2 years ago
I need help on how to solve this so anything is good :)
DanielleElmas [232]

Answer:

STUV is a square

Step-by-step explanation:

segment length² = (x-x₁)² + (y-y₁)²

ST²: (-9 - 1)2 + (14 - 10)² = (-10)² + 4² = 116   (the rest follow this formula)

TU² = 116    TV² = 232    SU² = 232   SV² = 116   UV² = 116

ST = TU =SV = UV  (4 sides congruent)

TV = SU  (diagonal equal)

This is a square

4 0
2 years ago
HELPPP????
kkurt [141]

Answer:

How are this equation and the equation of the line related? They both use the same variable to put it together. What does this relationship mean about any triangle created using this line? They are both put together so it would fit on the graph.

Step-by-step explanation:

The graph shows 1:2, where it's at. And they fit well because the numbers are next to each other. On the y axis, it's 2, right? And on the x axis it's 1, right? So it's 1:2 if that's what you're asking?

6 0
3 years ago
Read 2 more answers
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