Answer:
Check the solution in both equations. The solution is ( − 1, 2). Solve the system by graphing: {− x + y = 12 x + y = 10 . Solve the system by graphing: {2x + y = 6 x + y = 1 . In all the systems of linear equations so far, the lines intersected and the solution was one point.
Hope it helps!!!
First we need to find where the 2 graphs intercept.
x^2 + 3 = - (x^2 - 4x + 4) + 7
x^2 + 3 = -x^2 + 4x + 3
2x^2 - 4x = 0
2x(x - 2)
x = 0 , 2. are x coordinates of the 2 intercepts.
Holding what.......? can u be more specific?
The answer for this problem is 2 since it is not specified whether it is adjacent to the right or adjacent to the left.
If it is adjacent to the right, the answer is:
p (k) = 2 * p(1) + 2 * k
If the is adjacent to the left, the answer is:
P (k) = 2 *p(1) +2 * (k-2)
