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natita [175]
2 years ago
7

Answer for these! Please quickly

Mathematics
1 answer:
hram777 [196]2 years ago
5 0

Answer:

1: 233 (E)

2: 10,920 (C)

3: 241.87 (F)

4: 12600 (B)

Step-by-step explanation:

Use the Pythagorean Theorem to find the hypotenuse (the missing side length):

a^{2} + b^{2} = c^{2} \\c = \sqrt{a^{2} + b^{2}}

To find area of triangle:

A = 1/2 • base • height

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If the original quantity is 14 and the new quantity is 22, which of these is the best estimate for the percent of change?
julsineya [31]
D 22-14=8 14-7=7 7 of 14=50% so i think that’s the best estimate
8 0
3 years ago
Cooper was out at a restaurant for dinner when the bill came. His dinner came to $18. After adding in a tip, before tax, he paid
ozzi

Answer: Copper paid 13%

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What is the value of x? Enter your answer in the box. Ft Triangle V T K with segment T Y such that Y is on segment V K, between
Yanka [14]

Answer:

x=47 feet

Step-by-step explanation:

Since angle VTY is congruent to angle VTK, segment TY bisects angle VTK. Since Y is on segment VK, between V and K, we can use the Angle Bisector Theorem, which states that:

\frac{VY}{YK}=\frac{VT}{TK}

\frac{22}{YK}=\frac{77}{87.5}

YK=\frac{22{\times}87.5}{77}

YK=25 feet

Now, X=VY+YK

Substituting the values, we get

X=22+25

X=47 feet

6 0
3 years ago
Read 2 more answers
Kinda forgot how to do this but i got 894.09 for my answer not sure if im right
Andreas93 [3]
You correct the answer is 894.09
7 0
3 years ago
What is the interquartile range of the data set?
anastassius [24]

The interquartile range of the data set will be 30.

<u><em>Explanation</em></u>

Given data set: { 40, 48, 62, 60, 62, 40, 25, 50, 20, 30, 55 }

First we will rearrange the data in numeric order. So...

{ 20, 25, <u><em>30</em></u>, 40, 40, 48, 50, 55, <u><em>60</em></u>, 62, 62 }

Here the middle value in the set is 48. So, the median is 48 and it is diving the whole set into two different data sets. The median of the first set is 30 and median of the second set is 60.

That means, Lower quartile(Q₁) = 30 and Upper quartile(Q₃) = 60

So, the interquartile range of the data set: IQR= Q₃ - Q₁ = 60 - 30 = 30




6 0
3 years ago
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