1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Yuliya22 [10]
3 years ago
11

Change 1m2 in to cm2, mm2 and km2​

Physics
1 answer:
tresset_1 [31]3 years ago
7 0

Answer:

1m² = 10000cm²

1m² = 1000000mm²

1m² = 1 × 10^-6

Explanation:

When coverting from square meter to square centimetre, multiply the area value by 10.

When coverting from square meter to millimetre, multiply the area value by 10⁶ ( 1 million )

When converting from meter square to kilometre square, divide the area value by 10^-6 ( 0.000001)

You might be interested in
Calculate the pressure in pascals if a 560N is applied to an area of 1.6m².​
marshall27 [118]

Answer:

P = 350 [Pa]

Explanation:

The pressure is calculated by knowing the force and area. By means of the following formula can be calculated by means of the following equation.

Units of 1 [Pa] = 1 [N/m²]

P = F/A

where:

P = pressure [Pa]

F = force = 560 [N]

A = area = 1.6 [m²]

P = 560/1.6

P = 350 [Pa]

7 0
3 years ago
Which of the following is the visible part of the spectrum of light?
mestny [16]
The visible spectrum<span> is portion of the </span>electromagnetic spectrum<span> that is </span>visible <span>to the </span><span>human eye.
</span>gamma rays, <span>sound waves, </span><span>microwaves are not the part of spectrum of light, whereas color is the portion of spectrum of light.</span>
6 0
2 years ago
Read 2 more answers
A 10 kg mass stretches a spring 70 cm in equilibrium. Suppose a 2 kg mass is attached to the spring, initially displaced 25 cm b
NARA [144]

Answer:

Explanation:

1. Find spring constant k. From a free body diagram, you will get the forces on  the 10 kg mass, with a displacement d. It will be gravity pulling the mass down and the spring force pulling the mass up. The 10 kg mass is in equilibrium. The resulting equation will be:

F = m_1a = kd - m_1g = 0 => m_1g = kd => k = \frac{m_1g}{d}

2. Use the result from 1. to find the equations of motion. In general they are given by:

x(t) = Acos(\omega t + \phi), v(t) = -\omega Asin(\omega t + \phi), where ω is:\omega = \sqrt{\frac{k}{m_2}}=\sqrt{\frac{m_1g}{m_2d}}

To find the amplitude A and the phase angle Ф, use the given initial conditions:

m₂ = 2 kg, x(0) = -0.25 m, v(0) = 2m/s

-0.25 = Acos(\phi)\\2 = -\omega Asin(\phi)= -\sqrt{\frac{m_1g}{m_2d}}Asin(\phi)\\-0.24 = Asin(\phi)

Solving for Ф:

\frac{0.24}{0.25}=tan(\phi) => \phi = 0.76

Solving for A:

-0.25 = Acos(\phi) => A = -\frac{0.25}{cos(\phi)}=-0.35

The equation for x(t) is now:

x(t) = -0.35 cos(\sqrt{\frac{m_1g}{m_2d}t} +0.76)

The frequency f is given by:f = \frac{\omega}{2\pi}

The period T is given by:T = \frac{2\pi}{\omega}

8 0
3 years ago
A long, straight wire carries a current of 8.60
Kay [80]

First of all, we need to calculate the magnetic field generated by the wire at a distance r=3.90 cm=0.039 m, which is given by:

B=\frac{\mu_0 I}{2 \pi r}

where I=8.60 A is the current. Substituting numbers in the equation, we find

B=\frac{(4 \pi \cdot 10^{-7})(8.6 A)}{2 \pi (0.039 m)}=4.4 \cdot 10^{-5} T

And now we can calculate the force exerted on the electron, which is given by:

F=qvB

where q=1.6 \cdot 10^{-19} C is the charge of the electron and v=5.0 \cdot 10^4 m/s is its speed. Substituting data in the formula, we find

F=(1.6 \cdot 10^{-19}C)(5.00 \cdot 10^4 m/s)(4.4 \cdot 10^{-5} T)=3.5 \cdot 10^{-19} N

6 0
3 years ago
On a cello, the string with the largest linear density (1.44 x 10-2 kg/m) is the C string. This string produces a fundamental fr
Rus_ich [418]

Answer:

T=346.5N

Explanation:

From the question we are told that:

Density \rho=  (1.44 * 10^{-2} kg/m)

FrequencyF=93.0Hz

Lengthl=0.834m

Generally the equation for Frequency is mathematically given by

F=\frac{1}{2 l}sqrt{\frac{T}{\rho}}

Therefore

T=\rho(2 lF)^2

T= (1.44 * 10^{-2}*(2*0.834)(93.0))^2

T=346.5N

4 0
3 years ago
Other questions:
  • A cylinder has a length of 3.23 cm, a diameter of 1.75 cm, and a mass of 65.3 grams. What is the density of the cylinder? Based
    12·1 answer
  • Green light has a wavelength of 5.20 x 10^-7m. the speed of light is 3.00 * 10^8 m/s. what is the frequency of green light waves
    7·1 answer
  • Explain the relationships between gravity, mass, and distance. please write a paragraph
    11·1 answer
  • When 6.0 L of He(g) and 10. L of N2(g), both at 0oC and 1.0 atm, are pumped into an evacuated 4.0 L rigid container, the final p
    14·1 answer
  • Review Conceptual Example 16 as background for this problem. The water skier there has a mass of 73 kg. Find the magnitude of th
    7·1 answer
  • If the speed of an object were to triple, what would be the increase of kinetic energy?
    10·1 answer
  • The amount of energy absorbed by the substance and is generated by heat is called____________ energy. Matter or arrangement or t
    6·2 answers
  • What is the acceleration of a 160kg object if a force of 150N is applied to it?
    7·1 answer
  • How can I solve the following statement? A simple pendulum with a mass of 45g swings with a period of 11 s and an amplitude of 1
    10·1 answer
  • An engineer in a locomotive sees a car stuck on the track at a railroad crossing in front of the train . When the engineer first
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!