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AleksAgata [21]
2 years ago
9

which has more momentum, a large truck moving at 30 miles per hour or a small truck moving at 30 miles per hour?

Physics
1 answer:
lina2011 [118]2 years ago
8 0
A large truck because of potential energy
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Look at this model of an atom. Using a periodic table, which element does it represent?
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Nitrogen

Explanation:

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A basketball is thrown up into the air. It is released with an initial velocity of 8.5 m/s. How long does it take to get to the
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<h2>It takes 0.867 seconds to get to the top of its motion</h2>

Explanation:

We have equation of motion v = u + at

     Initial velocity, u = 8.5 m/s

     Final velocity, v = 0 m/s    - At maximum height

     Time, t = ?

     Acceleration , a = -9.81 m/s²

     Substituting

                      v = u + at  

                      0 = 8.5 + -9.81 x t

                      t = 0.867 s

  It takes 0.867 seconds to get to the top of its motion

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A 8.3-g wad of sticky clay is hurled horizontally at a 82-g wooden block initially at rest on a horizontal surface. The clay sti
Bingel [31]

Answer:

The speed of the clay before the impact was 106.35 m/s.

Explanation:

the only force doing work on the system is the frictional force, f, the work done by f is given by:

Wf = ΔK = Kf - Ki

The clay and the block will come to rest after sliding Δx = 7.50 m, if their intial speed is v and the combined mass is m and μ is the coefficient of friction and g is gravity,then:

         f×Δx = Ki

m×g×Δx×μ = 1/2×m×v^2

           v^2 = 2×g×Δx×μ

                  =  2×(9.8)×(7.50)×(0.650)

                  = 95.55

               v = 9.78 m/s

This is the veloty of clay and block after the clay hit the block.

if the velocity the clay and block attains after the impact is v and the initial speed of the clay is v1 and the mass is m and the speed of the block initially is V = 0 m/s and the mass is M, then according to the conservation of linear momentum:

m×v1 +M×V = v(m + M)

         m×v1 = v(m + M)

              v1 = v(m + M)/m

              v1 =  (9.78)(8.3×10^-3 + 82×10^-3)/(8.3×10^-3)

              v1 =  106.35 m/s

Therefore, the speed of the clay before the impact was 106.35 m/s.

3 0
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