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3 years ago

3. A supersonic jet flying at 145 m/s experiences uniform acceleration at the rate of 23.1 m/s2 for 20.0 s.

Physics

1 answer:

mihalych1998 [28]3 years ago

7 0

Answer:

A.607m/s | B.1.834Mach (speed of sound)

Explanation:

The plane's speed starts out at 145m/s, meaning after we calculate how many m/s it has accelerated, we must add that to the total.

If it accelerates for 20 seconds at a rate of 23.1m/s^2, this means that it accelerates 23.1m/s/s, or in words it gains 23.1 m/s every second. So, to calculate the gain in speed we simply multiply this by the duration of 20 seconds and get 462 m/s. Now, we add this to 145m/s, and get an end velocity of 607m/s.

For the plane's speed in terms of speed of sound, we divide 607m/s by the speed of sound, or 331m/s, and get ~1.834 Mach(speed of sound)

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Given:

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Speed, N = 1200 rpm

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Solution:

Torque, T = $\frac{P}{\omega }$

where,

$\omega = \frac{2\pi N}{60}$

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Now,

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$\tau _{key}$ = $\frac{F}{wl}$

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lyudmila [28]

Answer:

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Explanation:

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