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konstantin123 [22]
3 years ago
12

A driver moves with initial velocity of 40m/s accelerates uniformly at a rate of 12m/s2.  It attains a velocity 52m/s. calculate

the distance covered during the journey.
​
Physics
1 answer:
r-ruslan [8.4K]3 years ago
5 0

Answer:

The total distance covered is 46m

Explanation:

From the question, we have the following given parameters.

Initial Velocity = 40m/s

Acceleration = 12m/s²

Final Velocity = 52m/s

Required

Calculate the distance covered during the journey

The question can be solved using the following equation of motion.

v² = u² + 2as

Where

v = final velocity = 52m/s

u = initial velocity = 40m/s

a = acceleration = 12m/s²

s = distance = ?

By substituting the above values in the stated formula

v² = u² + 2as becomes

52² = 40² + 2 * 12 * s

2704 = 1600 + 24s

Subtract 1600 from both sides

2704 - 1600 = 1600 - 1600 + 24s

1104 = 24s

Divide both sides by 24

1104/24 = 24s/24

46 = s

Reorder

s = 46

Hence, the total distance covered is 46m

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A speed skater moving across frictionless ice at 9.2 m/s hits a 5.0 m wide patch of rough ice. She slows steadily, then continue
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Answer:

a = -5.10 m/s^2

her acceleration on the rough ice is -5.10 m/s^2

Explanation:

The distance travelled on the rough ice is equal to the width of the rough ice.

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Final speed v = 5.8 m/s

The time taken to move through the rough ice can be calculated using the equation of motion;

d = 0.5(u+v)t

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Substituting the given values;

t = 2(5)/(9.2+5.8)

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Substituting the values;

a = (5.8-9.2)/0.66667

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