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vazorg [7]
3 years ago
9

A proportional relationship is shown in the table below

Mathematics
1 answer:
CaHeK987 [17]3 years ago
7 0
3.33 or 1/.3 is the answer
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Ann will randomly select a bead from the package and then without replacing it randomly select a second bead based on the inform
san4es73 [151]

Answer:.......

Probability = \frac{g}{g+o}  + \frac{g-1}{g+o}

Step-by-step explanation:

Let g represent the number of green beads , and  o represent the number of orange beads.

due to the fact that Ann is selecting the bead without replacing i randomly

the probability (Pr) of Ann selecting a green bead and then an orange one  =\frac{g}{g+o} +\frac{g-1}{g+o}

7 0
4 years ago
Calculate the product 78.93 x 32.45
faust18 [17]

Answer:

The answer is 2 561,2785 !!!

3 0
3 years ago
4/16 Being Reduced Is ?
mamaluj [8]
The answer is 1/4 because all you have to really do is simplify
4 0
4 years ago
The perimeter of the following square can be found by using the expression 4(4x + 5).
Ber [7]
4(4x + 5)
4(4•7+5)
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132
4 0
3 years ago
Suppose that we have two identical boxes: box 1 and box 2. box 1 contains 5 red balls and 3 blue balls. box 2 contains 2 red bal
sineoko [7]

(a) The probability of drawing a blue marble at random from a given box is the number of blue marbles divided by the total number of marbles. We assume that the probability of selecting one of two boxes at random is 1/2 for each box.

... P(blue) = P(blue | box1)·P(box1) + P(blue | box2)·P(box2) = (3/8)·(1/2) + (4/6)·(1/2)

... P(blue) = 25/48 . . . . probability the ball is blue

(b) P(box1 | blue) = P(blue & box1)/P(blue) = (P(blue | box1)·P(box1)/P(blue)

... = ((3/8)·(1/2))/(25/48)

... P(box1 | blue) = 9/25 . . . . probability a blue ball is from box 1

8 0
4 years ago
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