1. You have that:
- The<span> lengths of the bases are (6x-1) units and 3 units.
- The midsegment has a length of (5x-3) units.
2. To solve this exercise, you must apply the formula for calculate the length of the midsegment of a trapezoid, which is shown below:
Midsegment=Base1+Base2/2
As you can see, the midsegment is half the sum of the bases of the trapezoid.
3. When you substitute the values, you obtain:
(5x-3)=[(6x-1)+3]/2
4. Now, you can solve the problem by clearing the "x":
</span>
(5x-3)=[(6x-1)+3]/2
2(5x-3)=6x-1+3
10x-6=6x+2
10x-6x=2+6
4x=8
x=8/4
x=2
Answer:
3
Step-by-step explanation:
A dog buried 18 bones
On Monday he dug up 1/2 of the bones
On Tuesday he dug up 1/3 of the bones
= 1/2 × 18
= 9
= 1/3×18
= 6
Therefore the remaining bones still buried in the ground can be calculated as follows
= 9+6
= 15
= 18-15
= 3
Hence 3 bones are still buried in the ground
Answer:
7 Miles is the answer.
Step-by-step explanation:
10*7=70.
I believe the answer is no solutions
7(x+y) because their both factors of 7
