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4 years ago

6

- George wanted to buy a car for $20,000. He knew he wanted to trade it in when the car had depreciated to $12,500. He knows tha

t the car depreciates at a rate of 8.75%. Rounded to the nearest tenth of a year, how long would it be before he would have to trade in his car?

1 answer:

777dan777 [17]4 years ago

3 0

Answer:

yes your are correct socyeahhh

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a) 1/27

b) 16

c) 1/8

Step-by-step explanation:

a) $x^{-3/2}$

One of the properties of the exponents tells us that when we have a negative exponent we can express it in terms of its positive exponent by turning it into the denominator (and changing its sign), so we would have:

$x^{-3/2}=\frac{1}{x^{3/2} }$

And now, solving for x = 9 we have:

$\frac{1}{x^{3/2}}=\frac{1}{9^{3/2} } =\frac{1}{27}$

b) $y^{4/3}$

This is already a positive rational exponent so we are just going to substitute the value of y = 8 into the expression

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Using the same property we used in a) we have:

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3 years ago

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gogolik [260]

Answer:

10 is your answer

Step-by-step explanation:

√((100 * 2)/2)

Simplify. First, follow the Parenthesis. Combine 100 with 2

100 * 2 = 200

Next, divide by 2

200/2 = 100

Root 100

√100 = √10 * √10 = 10

10 is your answer

~

An easier way to solving this is to first cancel out the 2's ( multiplying 2 and dividing 2 would do nothing), and just square rooting 100, giving you the answer 10.

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