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3 years ago

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Mathematics

2 answers:

m_a_m_a [10]3 years ago

7 0

Answer:

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Step-by-step explanation:

i need some persson wants to talk to me

Arada [10]3 years ago

6 0

Frick jejeuehehehjwuwikejejdunoxojrnwodij jord

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The scale of a map is 1¼ inch = 35 miles. If the distance from two points are 140 miles apart, how far are they away on the map?

slavikrds [6]

Answer:

5 inches

Step-by-step explanation:

140 / 35 = 4 x 1.25 = 5 inches

3 0

3 years ago

Find the 2 critical points of the given function and then determine whether it is a local maximum, local minimum, or saddle poin

grandymaker [24]

Answer:

Step-by-step explanation:

Given is a function f in two variables as

$f(x, y) = (x − y)(xy − 9)$

To find critical points of the given function and also to find max, min or saddle point.

Find the partial derivatives

$f(x,y) = x^2y-xy^2-9x+9y$

$f_x=2xy-y^2-9\\f_y =x^2-2xy+9\\f_{xy} =2x-2y = f_{yx}$

$f_{xx}=2y\\ f_{yy}=-2x$

Equate first derivatives to 0

Adding fx and fy we get

$x^2-y^2 =0\\$

x=±y

Only real roots are (x,y) =(3,3) and (-3,-3)

$D(3,3)=f_{xx}(3,3) f_{yy}(3,3)-f_{xy}^2(3,3) \\=-36-0$

(3,3) is a saddle point

$D(-3,-3) = -36$

(-3,-3) is also a saddle point.

7 0

3 years ago

Please also solve this

Virty [35]

Answer:

56 HAHHHAH K.HFGIUWFV,

Step-by-step explanation:

3 0

3 years ago

HELP ASAP!!! 5. The following two triangles are similar. Find x. х 6 56 48 5

ivanzaharov [21]

Answer:

x = 7

Step-by-step explanation:

The yellow triangle to the green triangle, is dilated to 1/8 of its original size. So 56/8 = 7

So x = 7

8 0

3 years ago

Read 2 more answers

The speeds of vehicles traveling on a highway are normally distributed with a population standard deviation of 7 miles per hour

True [87]

Answer: $(56.03\ ,63.97)$

Step-by-step explanation:

Given : The speeds of vehicles traveling on a highway are normally distributed .

Standard deviation: $\sigma: 7$

Since , sample size : $n=20$ , which is small sample (n<30) so the test applied here is a t-test.

Degree of freedom= $n-1=20-1=19$

Sample mean : $\overline{x}=60$

Level of significance : $1-\alpha:0.98$

Then , significance level : $\alpha: 1-0.98=0.02$

Using t-distribution table , Critical value : $\text{t-score}=t_{n-1, \alpha/2}= 2.539483$

The confidence interval for population mean is given by :-

$\overline{x}\pm t_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}$

$60\pm( 2.539483)\dfrac{7}{\sqrt{20}}\approx60\pm3.97=(56.03\ ,63.97)$

Hence, a 98% confidence interval for the population mean= $(56.03\ ,63.97)$

4 0

3 years ago