Hello from MrBillDoesMath!
Answer:
27 x^2 sqrt(x^3) sin(x^3) - 9/2 sqrt(x^1/2) sin(x^1/2)*x^(-1/2)
Discussion:
Let f(t) - 9 sqrt(t) sin(t), then
y' = f(x^3) * d(x^3)/dx - f(sqrt(x)) * d(x^1/2)/dx
= (9 sqrt(x^3)sin(x^3)) * 3x^2 - (9 sqrt(x^1/2)sin(x^1/2)) * (1/2) x^-(1/2)
= 27 x^2 sqrt(x^3) sin(x^3) - 9/2 sqrt(x^1/2) sin(x^1/2)*x^(-1/2)
Hope I didn't make a "bozo" error differentiating things!
Thank you,
MrB
Answer:
Slope is 1/5 and equation is 4-2 / 10-0
Step-by-step explanation:
Its equation is 4-2 / 10-0
-2/-10 = 1/5 Slope is 1/5
One way to do it is to find an explicit formula for the
th term.
The pattern suggests that the
th term is given by
, and so the fifth term is
.
Another way to do it would be to plug
into the recursive formula to find
, then
, and so on.