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Mice21 [21]
1 year ago
13

Ch of these is the absolute value parent function?

Mathematics
1 answer:
Andreyy891 year ago
8 0

Answer:

\text{C.} \: f(x) \:  =  \:  |x|

Step-by-step explanation:

To identify the absolute value of a number, it will always be represented between two sticks.

<h3><em><u>MissSpanish</u></em></h3>
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If A is an n× n matrix, then det A = det AT . Verify this theorem for 2 × 2 matrices.
Bond [772]

Answer:

Verified

Step-by-step explanation:

Let A matrix be in the form of

\left[\begin{array}{cc}a&b\\c&d\end{array}\right]

Then det(A) = ad - bc

Matrix A transposed would be in the form of:

\left[\begin{array}{cc}a&c\\b&d\end{array}\right]

Where we can also calculate its determinant:

det(AT) = ad - bc = det(A)

So the determinant of the nxn matrix is the same as its transposed version for 2x2 matrices

4 0
3 years ago
A coin bank has 250 coins dimes and quarters worth 39.25 how many of each type of coins are there?
Maurinko [17]
Set up a system of equations.

0.10d + 0.25q = 39.25
d + q = 250

Where 'd' represents the number of dimes, and 'q' represents the number of quarters.

d + q = 250

Subtract 'q' to both sides:

d = -q + 250

Plug in '-q + 250' for 'd' in the 1st equation:

0.10(-q + 250) + 0.25q = 39.25

Distribute 0.10:

-0.10q + 25 + 0.25q = 39.25

Combine like terms:

0.15q + 25 = 39.25

Subtract 25 to both sides:

0.15q = 14.25

Divide 0.15 to both sides:

q = 95

Now plug this into any of the two equations to find 'd':

d + q = 250

d + 95 = 250

Subtract 95 to both sides:

d = 155

So there are 95 quarters and 155 dimes.
8 0
3 years ago
Read 2 more answers
The percent of concentration of a certain drug in the bloodstream x hours after the drug is administered is given by K(x) 5x/x^2
Olegator [25]

Given :

The percent of concentration of a certain drug in the bloodstream x hours after the drug is administered is given by K(x) = \dfrac{5x}{x^2+9}.

To Find :

Find the time at which the concentration is a maximum. b. Find the maximum concentration.

Solution :

For maximum value of x, K'(x) = 0.

K'(x) = \dfrac{5(x^2+9)- 5x(2x)}{(x^2+9)^2}=0\\\\5x^2+45-10x^2=0\\\\5x^2 = 45\\\\x = \pm 3

Since, time cannot be negative, so ignoring x = -3 .

Putting value of x = 3, we get, K(3) = 15/( 9 + 9) = 5/6

Therefore, maximum value drug in bloodstream is 5/6 at time x = 3 units.

Hence, this is the required solution.

5 0
2 years ago
Where would you insert parentheses to make the statement true?
9966 [12]
Just around the 15 and 3. So it would be

(15-3)x4+9=57

This is because (15-3)= 12
12x4=48
48+9= 57
8 0
3 years ago
Read 2 more answers
A^4 b^2÷4a^3 b^-2<br><img src="https://tex.z-dn.net/?f=%20%20%7Ba%7D%5E%7B4%7D%20%7Bb%7D%5E%7B2%7D%20%20%5Cdiv%204%20%7Ba%7D%5E%
hichkok12 [17]
A^7 /4
That is the simplification
7 0
1 year ago
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