Question

Solve image below:

Answer 1

Answer: $x=\frac{6}{-3y+8}$

Step-by-Step Explanation:

Let's solve for $x$.

$\frac{x-2}{3y-5} =\frac{x}{3}$

Step 1: Multiply both sides by $3y-5$.

$x-2=\frac{3xy-5x}{3}$

Step 2: Multiply both sides by $3$.

$3x-6=3xy-5x$

Step 3: Add $-3xy$ to both sides.

$3x-6+-3xy=3xy-5x+-3xy$

$-3xy+3x-6=-5x$

Step 4: Add $5x$ to both sides.

$-3xy+3x-6+5x=-5x+5x$

$-3xy+8x-6=0$

Step 5: Add $6$ to both sides.

$-3xy+8x-6+6=0+6$

$-3xy+8x=6$

Step 6: Factor out variable $x$.

$x(-3y+8)=6$

Step 7: Divide both sides by $-3y+8$.

$\frac{x(-3y+8)}{-3y+8}=\frac{6}{y-3y+8}$

$x=\frac{6}{-3y+8}$

Answer:

$x=\frac{6}{-3y+8}$