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3 years ago

Please help. 6-12 Picture below

Mathematics

1 answer:

vladimir1956 [14]3 years ago

6 0

Answer:

21v31f3dd

Step-by-step explanation:

c123d

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PLS PLS HELP ASAP IT IS FOR A TEST

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3 years ago

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Help if you can if you can't it's OK 5 points

LenKa [72]

Answer:

3,500

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20,000×0.7=14,000 students are accepted

Of these, 25% enroll.

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3 years ago

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Find the average (mean) of the given set of data. 22,15,31,40,27

Rudiy27

Answer:

Step-by-step explanation:

Hi there!

We are given this set of data:

22, 15, 31, 40, 27

And we want to find the average (or the mean) of the set

To find the mean, we add up all of the values of the data set and then divide it by how many pieces of data we have

So first, add 22, 15, 31, 40 and 27 together

22+15+31+40+27=135

We have 5 pieces of data, so divide 135 by 5

135/5=27

The mean is 27

Hope this helps!

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3 years ago

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Which expression is equal to 9/10 ? A. 9x 1/10 B. 10x 1/9 C. 9/9x 10/10 D. 1/10 x 9/10

nikitadnepr [17]

A because 9 can be interpreted as 9/1 so 9/1*1/10 is 9/10. Hope you find this helpful...

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3 years ago

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A quality analyst of a tennis racquet manufacturing plant investigates if the length of a junior's tennis racquet conforms to th

Burka [1]

Answer:

Confidence interval : $21.506$ to $24.493$

Step-by-step explanation:

A quality analyst selects twenty racquets and obtains the following lengths:

21, 25, 23, 22, 24, 21, 25, 21, 23, 26, 21, 24, 22, 24, 23, 21, 21, 26, 23, 24

So, sample size = n =20

Now we are supposed to find Construct a 99.9% confidence interval for the mean length of all the junior's tennis racquets manufactured at this plant.

Since n < 30

So we will use t-distribution

Confidence level = 99.9%

Significance level = α = 0.001

Now calculate the sample mean

X=21, 25, 23, 22, 24, 21, 25, 21, 23, 26, 21, 24, 22, 24, 23, 21, 21, 26, 23, 24

Sample mean = $\bar{x}=\frac{\sum x}{n}$

Sample mean = $\bar{x}=\frac{21+25+23+22+24+21+25+21+23+ 26+ 21+24+22+ 24+23+21+ 21+ 26+23+ 24}{20}$

Sample mean = $\bar{x}=23$

Sample standard deviation = $\sqrt{\frac{\sum(x-\bar{x})^2}{n-1}}$

Sample standard deviation = $\sqrt{\frac{(21-23)^2+(25-23)^2+(23-23)^2+(22-23)^2+(24-23)^2+(21-23)^2+(25-23)^2+(21-23)^2+(23-23)^2+(26-23)^2+(21-23)^2+(24-23)^2+(22-23)^2+(24-23)^2+(23-23)^2+(21-23)^2+(21-23)^2+(26-23)^2+(23-23)^2+(24-23)^2}{20-1}}$

Sample standard deviation= s = $1.72$

Degree of freedom = n-1 = 20-1 -19

Critical value of t using the t-distribution table $t_{\frac{\alpha}{2}$ = 3.883

Formula of confidence interval : $\bar{x} \pm t_{\frac{\alpha}{2}} \times \frac{s}{\sqrt{n}}$

Substitute the values in the formula

Confidence interval : $23 \pm 1.73 \times \frac{1.72}{\sqrt{20}}$

Confidence interval : $23 -3.883 \times \frac{1.72}{\sqrt{20}}$ to $23 + 3.883 \times \frac{1.72}{\sqrt{20}}$

Confidence interval : $21.506$ to $24.493$

Hence Confidence interval : $21.506$ to $24.493$

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4 years ago

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