Answer:
Amount invested at 8 % rate = x = $ 15000
Amount invested at 9 % rate = 34000 - x = 34000 - 15000 = $ 19000
Step-by-step explanation:
Total Amount = $ 34000
Let amount invested at 8 % rate = x
Amount invested at 9 % rate = $ 34000 - x
Total interest = $ 2910
![2910 = \frac{x (8) (1)}{100} + \frac{(34000-x) (9) (1)}{100}](https://tex.z-dn.net/?f=2910%20%3D%20%5Cfrac%7Bx%20%288%29%20%281%29%7D%7B100%7D%20%2B%20%5Cfrac%7B%2834000-x%29%20%289%29%20%281%29%7D%7B100%7D)
291000 = 8 x + 306000 - 9 x
x = 306000 - 291000
x = 15000
So amount invested at 8 % rate = x = $ 15000
Amount invested at 9 % rate = 34000 - x = 34000 - 15000 = $ 19000
Answer:
If you want them at the same exact point then since the theif is 9 steps ahead it
will take 3 seconds
Step-by-step explanation:
Robber:
<em>starts at 9</em>
<em>starts at 9add on 5 and you get 14</em>
<em>starts at 9add on 5 and you get 14add 5 more you get 19</em>
<em>starts at 9add on 5 and you get 14add 5 more you get 19and another 5 would give you 24</em>
Police:
<em>is</em><em> </em><em>at</em><em> </em><em>0</em><em> </em><em>meters</em><em> </em>
<em>add</em><em> </em><em>8</em><em> </em><em>any</em><em> </em><em>you</em><em> </em><em>get</em><em> </em><em>8</em>
<em>add</em><em> </em><em>8</em><em> </em><em>more</em><em> </em><em>and</em><em> </em><em>you</em><em> </em><em>get</em><em> </em><em>1</em><em>6</em>
<em>and</em><em> </em><em>another</em><em> </em><em>8</em><em> </em><em>would</em><em> </em><em>get</em><em> </em><em>you</em><em> </em><em>to</em><em> </em><em>2</em><em>4</em>
0.1 i guess ok so try my question but im not 100 sure its correct
Step-by-step explanation:
It's 6r+5y. But it's not in the option
Answer:
P(X < 80) = 0.89435.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
![\mu = 60, \sigma = 16](https://tex.z-dn.net/?f=%5Cmu%20%3D%2060%2C%20%5Csigma%20%3D%2016)
P(X < 80)
This is the pvalue of Z when X = 80. So
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{80 - 60}{16}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B80%20-%2060%7D%7B16%7D)
![Z = 1.25](https://tex.z-dn.net/?f=Z%20%3D%201.25)
has a pvalue of 0.89435.
So
P(X < 80) = 0.89435.