Ask question

Ask question

All categories

Lady bird [3.3K]

3 years ago

12

Ranger has 15 problems on his Spanish Pre-Test. He doesn't want to do the whole test in one day, so he decides to do half today,

and half the next day. How many problems should he do for each day?

1 answer:

g100num [7]3 years ago

4 0

Well 15 divided by 2 would be 7.5.

You might be interested in

Gerard ran out of tile for his patio.The width of the remaining area 2 2/9 feet.The length of the remaning area is 7 feet.How mu

nikklg [1K]

Length X Width =
2 x 7 = 14
2/9 x 7 = 44/9
14 + 44/9 = 18 8/9
He has 18 8/9 feet left to tile.

4 0

3 years ago

On February 13th you deposit you’re bank account .on April 12th you withdraw $125 and on May 6th you deposit$25.how much money d

timama [110]

How much was deposited into the bank account?

7 0

3 years ago

Read 2 more answers

An engineer is comparing voltages for two types of batteries (K and Q) using a sample of 75 type K batteries and a sample of 46

lorasvet [3.4K]

The decision rule for rejecting the null hypothesis, considering the t-distribution, is of:

|t| < 1.9801 -> do not reject the null hypothesis.

|t| > 1.9801 -> reject the null hypothesis.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if there is not enough evidence to conclude that the mean voltage for these two types of batteries is different, that is, the subtraction of the sample means is of zero, hence:

$H_0: \mu_1 - \mu_2 = 0$

At the alternative hypothesis, it is tested if there is enough evidence to conclude that the mean voltage for these two types of batteries is different, that is, the subtraction of the sample means different of zero, hence:

$H_1: \mu_1 - \mu_2 \neq 0$

We have a two-tailed test, as we are testing if the mean is different of a value.

Considering the significance level of 0.05, with 75 + 46 - 2 = 119 df, the critical value for the test is given as follows:

|t| = 1.9801.

Hence the decision rule is:

|t| < 1.9801 -> do not reject the null hypothesis.

|t| > 1.9801 -> reject the null hypothesis.

More can be learned about the t-distribution in the test of an hypothesis at brainly.com/question/13873630

#SPJ1

3 0

1 year ago

The following is a linear programming formulation of a labor planning problem. There are four overlapping shifts, and management

dexar [7]

Answer:

d. 15

Step-by-step explanation:

Putting the values in the shift 2 function

X1 + X2 ≥ 15

where x1= 13, and x2=2

13+12≥ 15

15≥ 15

At least 15 workers must be assigned to the shift 2.

The LP model questions require that the constraints are satisfied.

The constraint for the shift 2 is that the number of workers must be equal or greater than 15

This can be solved using other constraint functions e.g

Putting X4= 0 in

X1 + X4 ≥ 12

gives

X1 ≥ 12

Now Putting the value X1 ≥ 12 in shift 2 constraint

X1 + X2 ≥ 15

12+ 2≥ 15

14 ≥ 15

this does not satisfy the condition so this is wrong.

Now from

X2 + X3 ≥ 16

Putting X3= 14

X2 + 14 ≥ 16

gives

X2 ≥ 2

Putting these in the shift 2

X1 + X2 ≥ 15

13+2 ≥ 15

15 ≥ 15

Which gives the same result as above.

6 0

3 years ago

1. What is the sum of 1/9, 2/3, and 5/18?<br> O A. 30<br> O B. 12/9<br> O C. 19/18<br> O D. 4/15

Serhud [2]

Answer:

C. 19/18

Step-by-step explanation:

$\frac{1}{9} + \frac{2}{3} + \frac{5}{18 } = \frac{2}{18} + \frac{12}{18} + \frac{5}{18} = \frac{19}{18}$

So the answer is C. 19/18

6 0

2 years ago