5000(1+.085/4)^n=1000
to find n use log:
1.02125^n
N X log1.02125
when computed=32.9
round to 33 quarters compounded
33/4
equals to 8 years 3 months
Answer:
-9.375
Step-by-step explanation:
2 1/2 x (-3 3/4) = -9.375
Answer:
24/45 or 9/15
Step-by-step explanation:
none of these is equivalent to 6:10
Let's call n the number of days Marika's been training for the race, and
the distance she runs on the nth day in meters. After the first day, when n = 1, she runs 100 meters, so

On the second day, she runs an additional 4 meters, on the third day, another 4, and so on. Here's what that looks like mathematically:

It would be easier to write this continued addition as multiplication, in which case those same equations would look like

Notice that, in every case, the number 4 is being multiplied by is 1 less than n. We could even write for our first term that
. In general, we can say that

Which is expressed by option B.
(Bonus: What piece of information from this question did we not need to use here?)