look at picture, need to know net force, whether they are balanced or unbalanced and whether they are accelerated or not acceler
ated!
1 answer:
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Answer:
Explanation:
Since the wire is infinitely long, we will use Gauss' Law:
We will draw an imaginary cylindrical surface with height h around the wire. The electric flux through the imaginary surface will be equal to the net charge inside the surface.
In that case, the net charge inside the imaginary surface will be the portion of wire with height h. Then the charge of that portion will be equal to
The left-hand side of the Gauss' Law is the flux through the imaginary surface. Since we choose our surface as a cylinder, of which we know the area, we do not have to take the surface integral.
where R is the radius of the imaginary cylinder.
Finally, Gauss' Law gives
The vector expression is
As you can see, the electric field is independent from the height h, since that is merely an imaginary cylinder to apply Gauss' Law. In the end, what matters is the charge density of the wire and the distance from the wire.
All frequencies of light in hertz are in between
and
Light with a lower frequency than 4 * 10^14 Hz, are called infrared and can't be seen by human eye. Light with a higher frequency than 8 * 10^14 Hz, are called ultraviolet and can't bee seen by human eye.
Therefore, the maximum frequency of visible light in Hz, is 8 * 10^14 Hz
Light with a lower frequency than 4 * 10^14 Hz, are called infrared and can't be seen by human eye. Light with a higher frequency than 8 * 10^14 Hz, are called ultraviolet and can't bee seen by human eye.
Therefore, the maximum frequency of visible light in Hz, is 8 * 10^14 Hz
Answer:
The slope of a position-time graph can be calculated as:
where
is the increment in the y-variable
is the increment in the x-variable
We can verify that the slope of this graph is actually equal to the velocity. In fact:
corresponds to the change in position, so it is the displacement,
corresponds to the change in time
, so the time interval
Therefore the slope of the graph is equal to
which corresponds to the definition of velocity.