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Feliz [49]
3 years ago
14

A 20 kg block rests on a rough horizontal table. A rope is

Physics
1 answer:
goldenfox [79]3 years ago
5 0

Answer:

So we are applying 80 N on the block, 20kg in mass and it moves with the acceleration of 2.5 m/s/s

so we can find the force being applied on the block

F = ma

F = 20 X 2.5

F = 50 N

So only 50 N of the 80 N is being applied on the block.

Hence, the remaining 80-50 = 30 N force is being used to overcome friction

Force of Kinetic Friction = 30 N

Now, in this case the Normal Force will be equal to the Force applied by gravity(Mg)

So, Normal Force = 200 N

Coefficient of kinetic friction = Force of Kinetic Friction / Normal Force

Coefficient of kinetic friction = 30 / 200

Coefficient of Kinetic Friction = 0.15

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A gas undergoes a process in a piston–cylinder assembly during which the pressure-specific volume relation is pv1.3 = constant.
Galina-37 [17]

Answer:

Change in specific internal Energy=250\ \rm Btu/lb

Explanation:

Given:

  • Mass of the gas, m=0.4 lb
  • Initial pressure and volume are p_1=160\ \rm lbf/in^2\ and\ v_1=1\ \rm ft^3\\
  • Final pressure and temperature are p_1=480\ \rm lbf/in^2
  • Heat transfer from the gas is 2.1 Btu

Since the process is isotropic we have

p_1v_1^{1.3}=p_2v_2^{1.3}\\160\times 1^{1.3}=480\times v_2^{1.3}\\v_2=0.43\ \rm ft^3\\

So the final volume of the gas is calculated.

Work in any isotropic is given by w

w=\dfrac{p_1v_1-P_2v_2}{n-1}\\\\w=\dfrac{160\times1-480\times0.43}{1.3-1}\\w=-154.67\ \rm Btu\\

According to the first law of thermodynamics we have

Q=\Delta U+w\\-2.1=\Delta U-154.67\\\Delta U=152.56\ \rm Btu\\

So the Specific Internal Change is given by

\Delta u=\dfrac{\Delta U}{m}\\\Delta u=\dfrac{152.56}{0.4}\\\Delta u=250\ \rm Btu/lb

So the specific Change in Internal energy is calculated.

6 0
3 years ago
A particle with charge 3.20×10−19 c is placed on the x axis in a region where the electric potential due to other charges increa
lys-0071 [83]

Answer:

-5 V

Explanation:

The charged particle (which is positively charged) moves from point A to B, and its kinetic energy increases: it means that the particle is following the direction of the field, so its potential energy is decreasing (because it's been converted into potential energy), therefore it is moving from a point at higher potential (A) to a point at lower potential (B). This means that the value

vb−va

is negative.

We can calculate the potential difference between the two points by using the law of conservation of energy:

\Delta K+ \Delta U=0\\\Delta K + q\Delta V=0

where:

\Delta K=+1.6\cdot 10^{-18} J is the change in kinetic energy of the particle

q=3.2\cdot 10^{-19} C is the charge of the particle

\Delta V =V_b-V_a is the potential difference

Re-arranging the equation, we can find the value of the potential difference:

\Delta V=V_b-V_a = -\frac{\Delta K}{q}=-\frac{1.6\cdot 10^{-18} J}{3.2\cdot 10^{-19} C}=-5 V

8 0
4 years ago
A ball rolls down a hill and hits a box. The momentum of the ball decreases. Which happens to the momentum? Select one of the op
Irina-Kira [14]
<span>So we want to know what happens to the momentum of the ball that rolls down hill and hits a box. So we need to use the law of conservation of momentum which states that the momentum must be conserved. It cant be transformed into inertia or mass. It can only be transferred to other object via some interactions like collisions. So it has to be a. transferred to the box and that is the correct answer. </span>
7 0
3 years ago
Which of the following is a TRUE statement?
pshichka [43]

Answer:

e. All of these statements are false.

Explanation:

As we know that heat transfer take place from high temperature to low temperature.

It is possible to convert all work into heat but it is not possible to convert all heat in to work some heat will be reject to the surrounding.

The first law of thermodynamics is the energy conservation law.

Second law of thermodynamics  states that it is impossible to construct a device which convert all energy into work without rejecting the heat to the surrounding.

By using heat pump ,heat can transfer from cooler body to the hotter body.

Therefore all the answer is False.

5 0
4 years ago
PLEASE HELP!!!
crimeas [40]

Answer: potential to kinetic/mechanical

Explanation:

5 0
3 years ago
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