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1 year ago

In the mass spectrum of pentane, the presence of a peak with m/z = 15 is most likely to the detection of:_________-

1 answer:

3 0

In the mass spectrum of pentane, the presence of a peak with m/z = 15 is most likely due to the detection of A) methyl radical cation that has been lost from the spectrum.

<h3>Mass Spectrum</h3>

The m/z ratios of any ions contained in a sample displayed against their intensities that forms a mass spectrum.

The height of the peaks in any kind of mass spectrum denotes the relative abundance of the various components in the sample, and each peak in a mass spectrum displays a component that a distinct m/z is in the sample.

<h3>How do mass spectra function?</h3>

Only when a molecule has been transformed into a gas-phase ion can a mass spectrometer calculate the mass of the molecule.

In order to do this, it gives molecules an electrical charge and transforms the flow of electrically charged ions that results into a proportional electrical current that a data system can subsequently read.

<h3>Give an example of the mass spectral range.</h3>

Whenever any molecules are ionized in an ionization box, many different kinds of ions have been created.

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Complete Question

In the mass spectrum of pentane, the presence of a peak with m/z = 15 is most likely to the detection of: _________-

A) Methyl Radical

B) Ethyl Radical

C) Propyl Radical

D) Butyl Radical

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A chemist identifies compounds by identifying bright lines in their spectra. She does so by heating the compounds until they glo

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Answer:

a) λ = 189.43 10⁻⁹ m b) λ = 269.19 10⁻⁹ m

Explanation:

The diffraction network is described by the expression

d sin θ= m λ

Where m corresponds to the diffraction order

Let's use trigonometry to find the breast

tan θ = y / L

The diffraction spectrum is measured at very small angles, therefore

tan θ = sin θ / cos θ = sin θ

We replace

d y / L = m λ

Let's place in the first order m = 1

Let's look for the separation of the lines (d)

d = λ L / y

d = 501 10⁻⁹ 9.95 10⁻² / 15 10⁻²

d = 332.33 10⁻⁹ m

Now we can look for the wavelength of the other line

λ = d y / L

λ = 332.33 10⁻⁹ 8.55 10⁻²/15 10⁻²

λ = 189.43 10⁻⁹ m

Part B

The compound wavelength B

λ = 332.33 10⁻⁹ 12.15 10⁻² / 15 10⁻²

λ = 269.19 10⁻⁹ m

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3 years ago

an object of mass 6000 kg rests on the flatbed of a truck. it is held in place by metal brackets that can exert a maximum horizo

Otrada [13]

Answer:

minimum stopping distance will be d = 75 m

Explanation:

Maximum force exerted by the bracket is given as

F = 9000 N

now we know that mass of the object is

m = 6000 kg

so the maximum acceleration that truck can have is given as

$F = ma$

$9000 = 6000 a$

$a = 1.5 m/s^2$

now for finding minimum stopping distance of the truck

$v_f^2 - v_i^2 = 2a d$

$0^2 - 15^2 = 2(-1.5) d$

$d = 75 m$

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3 years ago

The speed of light in vacuum is exactly 299,792,458 m/s. A beam of light has a wavelength of 651 nm in vacuum. This light propag

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Answer:

$v=2.58\times10^8m/s$

Explanation:

The index of refraction is equal to the speed of light c in vacuum divided by its speed v in a substance, or $n=\frac{c}{v}$ . For our case we want to use $v=\frac{c}{n}$ , which for our values is equal to:

$v=\frac{c}{n}=\frac{299792458m/s}{1.16}=258441774.138m/s$

Which we will express with 3 significant figures (since a product or quotient must contain the same number of significant figures as the measurement with the <em>least</em> number of significant figures):

$v=2.58\times10^8m/s$

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Answer:

Explanation:

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Where are the answer choice ?