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BartSMP [9]
1 year ago
9

a small insect viewed through a convex lens is 2.5 cm from the lens and appears 2.5 times larger than its actual size. part a wh

at is the focal length of the lens? express your answer using two significant figures. f
Physics
1 answer:
Amiraneli [1.4K]1 year ago
5 0

The lens' focal length is 1.5 cm, and its focal length is equal to half its radius of curvature, as shown by the formula f=R2 f = R 2, where f seems to be the focal length as well as R is indeed the radius of curvature.

<h3>What does focal length mean?</h3>

When a lens is focussed at infinity, the focal length of the lens is discovered. We can determine the angle of view, or the amount of the scene will be caught, and the magnification, or how big the individual elements will be, by measuring the focal length of the lens. A narrower field of view and a higher magnification result from a longer focal length.

<h3>How do focal length or wavelength work?</h3>

As wavelength and refractive index are inversely connected, the focal length of a lens varies inversely with each of them. The focal length of a lens varies directly with wavelength of light employed. The main reason chromatic aberration occurs is due to this. No relationship exists between the focal length and the frequency of a light.

To know more about focal length visit:

brainly.com/question/16188698

#SPJ4

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An object of mass 2kg raised to a height 10m possess potential energy of 200J. What is the kinetic energy and potential energy a
Shtirlitz [24]

Explanation:

{\bold{\sf{\underline{Understanding \: the \: concept}}}}

✠ This question says that there is an object and its mass is 2 kg ; it's raised to a height 10 m and possess potential energy of 200 J. Now this question ask us to find the kinetic energy and the potential energy at a height 4 metre.

\bold{↬{   }}{\bold{\sf{\underline{Given \: that}}}}

✰ Mass = 2 kilograms

✰ Raised height = 10 metres

✰ Posses potential energy = 200 Joules

\bold{↬{   }}{\bold{\sf{\underline{To \: find}}}}

✰ Kinetic energy at a height 4 metre

✰ Potential energy at a height 4 metre

{\bold{\sf{\underline{Solution}}}}

✰ Kinetic energy at a height 4 metre = 120 J

✰ Potential energy at a height 4 metre = 80 J

{\bold{\sf{\underline{Using \: concepts}}}}

✰ Potential energy formula.

{\bold{\sf{\underline{Using \: formula}}}}

✰ Potential energy = mgh

{\bold{\sf{\underline{We \: also \: write \: these \: as}}}}

✰ Potential energy as P.E

✰ Mass as m

✰ Joules as J

✰ Height as h

✰ Raised height as g

{\bold{\sf{\underline{Full \: solution}}}}

<h3>✠ Let us find the Potential energy.</h3>

↦ Potential energy = mgh

↦ Potential energy = 2 × 10 × 4

↦ Potential energy = 20 × 4

↦ Potential energy = 80 J

<h3>✠ Now according to the question let us find the kinetic energy</h3>

↦ Kinetic energy = Posses potential energy - Finded potential energy

↦ Kinetic energy = 200 J - 80 J

↦ Kinetic energy = 120 Joules

4 0
3 years ago
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He back window of this car contains a heating element.The heating element is part of an electrical circuit connected to the batt
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What is the fault-current circuit breaker? Describe its function.
Nimfa-mama [501]

Answer:

A circuit breaker is a switching mechanism that interrupts the current that is irregular or fault. It is a mechanical system that interferes with high magnitude (fault) current flow and also performs a transfer operation. Hope this helps :)

Explanation:

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The total mechanical energy of a basketball is 400 J. If the kinetic energy is 286 J, what must the potential energy be?
ch4aika [34]

Answer:

the potential energy is 114 J.

Explanation:

Given;

total mechanical energy, E = 400 J

kinetic energy, K.E = 286 J

The potential energy is calculated as follows;

E = K.E +  P.E

where;

P.E is the potential energy

P.E = E - K.E

P.E = 400 J - 286 J

P.E = 114 J

Therefore, the potential energy is 114 J.

7 0
2 years ago
A swinging pendulum has a total energy of <img src="https://tex.z-dn.net/?f=E_i" id="TexFormula1" title="E_i" alt="E_i" align="a
Zolol [24]

Answer:

\frac{E_{2}}{E_{1}} \approx 1 -\frac{3\theta}{1-\theta} (for small oscillations)

Explanation:

The total energy of the pendulum is equal to:

E_{1} = m\cdot g \cdot (1-\cos \theta)\cdot L

For small oscillations, the equation can be re-arranged into the following form:

E_{1} \approx m\cdot g \cdot (1-\theta) \cdot L

Where:

\theta = \frac{A}{L^{2}}, measured in radians.

If the amplitude of pendulum oscillations is increase by a factor of 4, the angle of oscillation is 4\theta and the total energy of the pendulum is:

E_{2} \approx m\cdot g \cdot (1-4\theta)\cdot L

The factor of change is:

\frac{E_{2}}{E_{1}} \approx \frac{1 - 4\theta}{1-\theta}

\frac{E_{2}}{E_{1}} \approx 1 -\frac{3\theta}{1-\theta}

3 0
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