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dimaraw [331]
2 years ago
13

Factorize 2^x+7 + 2^x+6

Mathematics
1 answer:
joja [24]2 years ago
8 0

Answer:

Step-by-step explanation:

2^{(x+ 7)} + 2^{(x+ 6 )} = 2^{x} * 2^{7} + 2^{x}*2^{6}\\\\=2^{x} *(2^{7} + 2^{6})

= 2^{x} * 2^{6} ( 2+ 1)\\\\= 2^{x} * 2^{6} * 3

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The Power of a Power Rule. In this case, you basically multiply the two exponents together, and simplify (x^4)^9 to equal x^36
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The function(t)--4.87+18.75 is used to model the height of an object projected in the air, where h() is the height in
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The domain and range of the given function are equal to (0, 3.85) and (0, 18.75) respectively.

<h3>How to calculate the domain of the function?</h3>

In this exercise, you're given the following function h(t) = -4.87t² + 18.75t. Next, we would equate the function to zero (0) to determine its domain as follows:

0= -4.87t² + 18.75t.

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h(t) = -4.87t² + 18.75t

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Read more on domain here: brainly.com/question/17003159

#SPJ1

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Read image for instructions
Oliga [24]

The last part answers the first part for you, just look at the y-values.

In other words:

<em>A'</em><em> </em>(-8, 2)

<em>B'</em> (-4, 3)

<em>C'</em> (-2, 8)

<em>D'</em> (-10, 6)

Explanation:

When you reflect any point over the x-axis, the y-value of the ordered pair is going to change.

This makes sense especially considering that the x-axis is horizontal, so the only way you could cross is to move up or down. If you were to move left or right, you'd only be able to cross the y-axis, since it's vertical.

Now for the last part, as I mentioned above, if you are reflecting across the y-axis, the x-values of the ordered pair is going to change.

<em>A'</em><em>'</em> (8, 2)

<em>B'</em><em>'</em> (4, 3)

<em>C'</em><em>'</em> (2, 8)

<em>D'</em><em>'</em> (10, 6)

Take note that the only thing that changes for the respective value is its sign, while the number itself stays the same.

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Which shows a correct order to solve this story problem?
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Step B would be correct because you trying to find the total number of hours she reads in 8 days and not the difference. <span />
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