9514 1404 393
Answer:
20, 50
Step-by-step explanation:
Let x and y represent the two numbers.
x + y = 70 . . . . . . their sum is 70
2x +10 = y . . . . . . one is 10 more than twice the other
Using the second equation to substitute for y in the first equation, we have ...
x + (2x +10) = 70
3x = 60 . . . . . . . . . subtract 10
x = 20 . . . . . . . . . divide by 3
y = 70 -20 = 50 . . . find the other number
The two numbers are 20 and 50.
x + y = 24 where x and y are the 2 parts of diagonal Other diagonal wil be smaller that 24.
x^2 + z^2 = 13^2
y^2 + z^2 = 20^2 where z = 0.5 * length of smaller diagonal)
form last 2 equations
y^2 - x^2 = 20^2 - 13^2 = 231
now y = 24-x so we have
(24 - x)^2 - x^2 = 231
576 - 48x = 231
48x = 345
x = 7.1875
z^2 = 13^2 - 7.1875^2 = 117.34
z = 1.83
so smaller diagonal = 21.66 cm
looks like its the third choice.
Here we are given the expression:
Now let us equate it to zero to find x first,
Now subtracting 52 from the other side,
taking square root on both sides,
So we will get two values of x as ,
Now we can write square root -1 as i,
So our factors become,
Answer:
The final factored form becomes,
