Because a shoveling business is inly needed during winter and fall only if it snows and the leaves fall airplane manufacturing is used everyday in any type of season or weather
Answer:
5C
6C
7D
8B
Step-by-step explanation:
5) C because median is the middle of the set of numbers source A median is 4 source B median is 6 and 4 is 2 less than 6.
6) C because there are 6 numbers altogether and 1 6s on a dice so 6+6 because we have two dice and 2 6s on both so 2/12 or simplified 1/6
7) D because mean is all the numbers add up divided by the amount of numbers so 20+25+30+20+30 = 125 and 125 ÷ 5 = 25
8 B because mean is all the numbers add up divided by the amount of numbers so
5+6+7+8+8+8+8+8+8+9+9 = 76 ÷ by 10 is 7.6
7+7+7+7+8+8+8+8+10+10 = 80 ÷ by 10 = 8
8 + 7.6 = 15.6 ÷ 2 = 7.8 and B is closest to 7.8
This is not true.


where is
is any integer. So suppose we pick some value of
other than these, say
. Then

I have attached a chart of the given information. Using subtraction from 100 and the other totals, you should be able to figure out the answer. If not, comment and I will send the completed chart
Answer:
The probability that none of the LED light bulbs are defective is 0.7374.
Step-by-step explanation:
The complete question is:
What is the probability that none of the LED light bulbs are defective?
Solution:
Let the random variable <em>X</em> represent the number of defective LED light bulbs.
The probability of a LED light bulb being defective is, P (X) = <em>p</em> = 0.03.
A random sample of <em>n</em> = 10 LED light bulbs is selected.
The event of a specific LED light bulb being defective is independent of the other bulbs.
The random variable <em>X</em> thus follows a Binomial distribution with parameters <em>n</em> = 10 and <em>p</em> = 0.03.
The probability mass function of <em>X</em> is:

Compute the probability that none of the LED light bulbs are defective as follows:


Thus, the probability that none of the LED light bulbs are defective is 0.7374.