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3 years ago

Is there a way I can delete this account? I'm leaving brainly

Mathematics

2 answers:

DENIUS [597]3 years ago

4 0

Answer:

You can delete your account by going to your Profile Settings >> Privacy and clicking on the I want to delete my account<em> </em>box. Doing so submits a request for your account to be deleted.

user100 [1]3 years ago

4 0

Answer:

*sigh* there is no way :c

Step-by-step explanation:

You might be interested in

Penelope was reading a book at a rate

valentinak56 [21]

Answer:

Penelope can read 6 pages in 5 minutes.

Step-by-step explanation:

You would use the equation 1.2x = P

P=how many pages x=how many minutes

1.2(5) = 6

She can read 6 pages in 5 minutes

8 0

3 years ago

If the volume of a sphere inscribed in a cubic box is 36pi, find the surface area of the box

Kruka [31]

Answer:

Surface area of the cube = 216 square units

Step-by-step explanation:

Let the length of a side of a cube = x unit

Diameter of the sphere inscribed in this cube = length of a side of the cube

Volume of the sphere = $\frac{4}{3}\pi r^{3}$

Where r = radius of the sphere = $\frac{x}{2}$ units

36π = $\frac{4}{3}\pi (\frac{x}{2})^{3}$

36π = $\frac{4x^{3}\pi }{24}$

36×24 = 4x³

x = $\sqrt[3]{\frac{36\times 24}{4} }$

x = 6 units

Length of a side of the cube = 6 units

Surface area of the cube = 6×(Side)²

= 6×(6)²

= 216

= 216 square units

3 0

3 years ago

Sin theta+costheta/sintheta -costheta+sintheta-costheta/sintheta+costheta=2sec2/tan2 theta -1

sleet_krkn [62]

$\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}=\dfrac{2sec^2\theta}{tan^2\theta-1}$

From Left side:

$\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}\bigg(\dfrac{sin\theta+cos\theta}{sin\theta+cos\theta}\bigg)+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}\bigg(\dfrac{sin\theta-cos\theta}{sin\theta-cos\theta}\bigg)$

$\dfrac{sin^2\theta+2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}+\dfrac{sin^2\theta-2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}$

NOTE: sin²θ + cos²θ = 1

$\dfrac{1 + 2cos\theta sin\theta}{sin^2\theta-cos^2\theta}+\dfrac{1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}$

$\dfrac{1 + 2cos\theta sin\theta+1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}$

$\dfrac{2}{sin^2\theta-cos^2\theta}$

$\dfrac{2}{\bigg(sin^2\theta-cos^2\theta\bigg)\bigg(\dfrac{cos^2\theta}{cos^2\theta}\bigg)}$

$\dfrac{2sec^2\theta}{\dfrac{sin^2\theta}{cos^2\theta}-\dfrac{cos^2\theta}{cos^2\theta}}$

$\dfrac{2sec^2\theta}{tan^2\theta-1}$

Left side = Right side <em>so proof is complete</em>

8 0

3 years ago

Read 2 more answers

Find the unknown side length x.

Ganezh [65]

Answer:

x = $\sqrt{65}$

Step-by-step explanation:

The altitude of the triangle must equal 4 because it is a right triangle with another leg of 3 and a hypotenuse of 5 (reason is due to the pythagorean theorem)

Therefore, the triangle on the right has legs of 4 and 7 and, again, use the phythagorean theorem to find 'x' (the hypotenuse)

$4^{2}$ + $7^{2}$ = $x^{2}$