According to the condition, this equation has <u>two</u> solutions: -14/5 and 14/5.
Short explanation:
5|x|=14; ⇔ |x|=14/5; ⇒
PS. it's correct, if to substitute the values of 'x' into the condition/equation.
Answer:
4 and 5
Step-by-step explanation:
4 and 5 are the co efficients of c
Answer:
they both have 5 in common
if you were to reduce the fraction it would be 11/16 because
55 divided by 5 is 11 and 80 divided by 5 is 16
Step-by-step explanation:
Answer:
5, 42, 15, 82
Step-by-step explanation:
y=4x+2
22=4x+2
20=4x
5=x
y=4(10)+2
y=40+2
y=42
62=4x+2
60=4x
15=x
y=4(20)+2
y=80+2
y=82
Given:
13/8
First you have to see how many times 8 can go into the number 13. If you look, 8 can only go into 13 one time, leaving 5 left over.
13-8 = 5
1 with 5 left over
(Rather than writing 8/8, you must simplify to 1 to make it less redundant)
Since there is 5 left over from 8, you would then place it into the numerator place to get:
1 5/8
I hope this helps!
