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ziro4ka [17]
3 years ago
10

..................................................................................​

Mathematics
2 answers:
madreJ [45]3 years ago
8 0

Answer:

are you leaving.....please reply

Otrada [13]3 years ago
4 0

Answer:

..................................................................................

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Need help with this continuity problem.
ira [324]

In order to be continuous everywhere, we only need to satisfy continuity at x=10. For that to happen, we need to have

\displaystyle\lim_{x\to10^-}f(x)=\lim_{x\to10^+}f(x)=f(10)

By the function's definition, f(10)=2(10)-2=18. Compute the limits:

\displaystyle\lim_{x\to10^-}f(x)=\lim_{x\to10}2x-2=18

\displaystyle\lim_{x\to10^+}f(x)=\lim_{x\to10}-8x+b=-80+b

So we must have

18=b-80\implies b=98

3 0
3 years ago
Jose has $20 more than Sarah. Their combined mobey totals $90. Write and solve an algebric model to determine the amount of mone
scoray [572]

Let S= the amount of money Sarah has.

Let J= the amount of money Jose has

J= S+20

J+S=90

But we also know that J can equal S+20

So,

S+20+S=90

2S+20=90

2S=70

S=35

So Sarah has $35, and Jose has $35+$20, so he has 55$

6 0
3 years ago
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How many more ficton books than non fiction 2
Lena [83]

Answer:

what do you want us to solve

Step-by-step explanation:

i dont see anything to find a awnser

7 0
3 years ago
Suppose in a society where there are equal numbers of men and women. There is a 50% chance for each child that a couple gives bi
jeka57 [31]

Answer:

eventually the gender ratio of population in this society will be 50% male and 50% female.

Step-by-step explanation:

For practical purposes we will think that every couple is healthy enough to give birth as much children needed until giving birth a girl.

As the problem states, "each couple continue to have more children until they get a girl and once they have a girl they will stop having more children". Then, every couple will have one and only one girl.

  1. This girl would be the n-th child with a probability (0.5)^n.

We will denote for P(Bₙ) the probability of a couple to have exactly n boys.

Observe that statement 1 implies that:

P(B_{n-1})=(0.5)^{n}.

Then, the average number of boys per couple is given by

\sum^{\infty}_{n=1}(n-1)P(B_{n-1})=\sum^{\infty}_{n=1}(n-1)(\frac{1}{2} )^n=\sum^{\infty}_{n=2}n(\frac{1}{2} )^n=\\\\=\sum^{\infty}_{m=2}\sum^{\infty}_{n=m}(\frac{1}{2} )^n=\sum^{\infty}_{m=2}(\frac{1}{2} )^{m-1}=\sum^{\infty}_{m=1}(\frac{1}{2} )^{m}=1.\\

This means that in average every couple has a boy and a girl. Then eventually the gender ratio of population in this society will be 50% male and 50% female.

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4 years ago
HURRRYYYYYYY PLEASEEEEEEEE
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A it would be a aaaaaaaa
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