In order to be continuous everywhere, we only need to satisfy continuity at
. For that to happen, we need to have

By the function's definition,
. Compute the limits:


So we must have

Let S= the amount of money Sarah has.
Let J= the amount of money Jose has
J= S+20
J+S=90
But we also know that J can equal S+20
So,
S+20+S=90
2S+20=90
2S=70
S=35
So Sarah has $35, and Jose has $35+$20, so he has 55$
Answer:
what do you want us to solve
Step-by-step explanation:
i dont see anything to find a awnser
Answer:
eventually the gender ratio of population in this society will be 50% male and 50% female.
Step-by-step explanation:
For practical purposes we will think that every couple is healthy enough to give birth as much children needed until giving birth a girl.
As the problem states, "each couple continue to have more children until they get a girl and once they have a girl they will stop having more children". Then, every couple will have one and only one girl.
- This girl would be the n-th child with a probability
.
We will denote for P(Bₙ) the probability of a couple to have exactly n boys.
Observe that statement 1 implies that:
.
Then, the average number of boys per couple is given by

This means that in average every couple has a boy and a girl. Then eventually the gender ratio of population in this society will be 50% male and 50% female.