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3 years ago

13

Please help me with these problems; geometry is really getting on my nerves. T-T

2 answers:

ivolga24 [154]3 years ago

7 0

For #19 part A :

By vertical angles and then same side interior angles 3x + 2x = 180
5x = 180
x = 36

For #19 part B:

You are correct with the 35, but you missed the fact that the 105 angle is supplementary with the unknown angle inside the triangle. So:

180 - 105 = 75

Then:

180 = 35 + 75 + x
180 = 110 + x
x = 70

Last question:

Do you know what the symbol means? Text me and tell me and I can answer it for you. :)

lana [24]3 years ago

6 0

Veridian has great answers. I'm only posting this as a supplement to help provide the diagrams showing the various angles, that lead into the equations Veridian uses.

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Shaun and Trudy are selling raffle tickets. So far, Shaun has sold x tickets. Trudy has sold 3 more tickets than half the number

Kipish [7]

S=x
T=1/2x+3
Total= 1 1/2x + 3

5 0

3 years ago

A circle has a radius of 14 units. What is the area in square units of the circle in terms of π?

Snowcat [4.5K]

Area of circle = pi r²

14²= 196

196 x pi = 196pi

Area = 196pi units²

3 0

3 years ago

Please help me out :P

Veseljchak [2.6K]

cos θ = $\frac{-4\sqrt{65} }{65}$ , sin θ = $\frac{-7\sqrt{65} }{65}$ , cot θ = 4/7, sec θ = $\frac{-\sqrt{65} }{4}$ , cosec θ = $\frac{-\sqrt{65} }{7}$

<h3>What are trigonometric ratios?</h3>

Trigonometric Ratios are values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle.

Sin θ: Opposite Side to θ/Hypotenuse

Tan θ: Opposite Side/Adjacent Side & Sin θ/Cos

Cos θ: Adjacent Side to θ/Hypotenuse

Sec θ: Hypotenuse/Adjacent Side & 1/cos θ

Analysis:

tan θ = opposite/adjacent = 7/4

opposite = 7, adjacent = 4.

we now look for the hypotenuse of the right angled triangle

hypotenuse = $\sqrt{7^{2} + 4^{2} }$ = $\sqrt{49+16}$ = $\sqrt{65}$

sin θ = opposite/ hyp = $\frac{7}{\sqrt{65} }$

Rationalize, $\frac{7}{\sqrt{65} }$ x $\frac{\sqrt{65} }{\sqrt{65} }$ = $\frac{7\sqrt{65} }{65}$

But θ is in the third quadrant(180 - 270) and in the third quadrant only tan and cot are positive others are negative.

Therefore, sin θ = - $\frac{7\sqrt{65} }{65}$

cos θ = adj/hyp = $\frac{4}{\sqrt{65} }$

By rationalizing and knowing that cos θ is negative, cos θ = - $\frac{-4\sqrt{65} }{65}$

cot θ = 1/tan θ = 1/7/4 = 4/7

sec θ = 1/cos θ = 1/ $\frac{4}{\sqrt{65} }$ = - $\frac{-\sqrt{65} }{4}$

cosec θ = 1/sin θ = 1/ $\frac{\sqrt{65} }{7}$ = $\frac{-\sqrt{65} }{7}$

Learn more about trigonometric ratios: brainly.com/question/24349828

#SPJ1

5 0

1 year ago

a line with a slope of 1 passes through the point (5,10). what is the equation in this slope-intercept form?

patriot [66]

Answer:

y=x+5

Step-by-step explanation:

So first you need to plug everything into the point-slope formula which is

y-y1=m(x-x1)

m being the slope and y1 and x1 being the point (5,10)

So once you plug it in it should look like this: y-10=1(x-5)

Now you solve it

First you need to distribute 1 in 1(x-5) which is (x-5)

Now you have y-10=x-5

Then you add 10 to both sides which is y=x+5

Your answer is y=x+5

8 0

3 years ago

Could someone please help me solve this?

ryzh [129]

Answer:

40

Step-by-step explanation:

(2/5)*n - 6 = 10 Add 6 to both sides

(2/5)*n - 6 + 6 = 10 + 6 Combine

(2/5)*n = 16 Multiply both sides by 5/2

(5/2)(2/5)n = 16*(5/2)

n = 80 / 2

n = 40

6 0

3 years ago