All categories

3 years ago

does anyone know how to view what answers you got correct on a post test for plato/ edmentum? please give detailed instructions

Mathematics

1 answer:

Anna35 [415]3 years ago

7 0

Answer:

Step-by-step explanation:

For Plato just press the + button to add an introduction or whatever.

You might be interested in

Answer this for me, please.

Scilla [17]

Answer:

the answer would be .5 miles

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

I need help with number 3 and 5

shepuryov [24]

3 is no cuz obtuse angle is >90 degrees, all the angles together must equal 180 degrees, and if you try it, you get no. 5 is 25% of 45, which is $11.25.

5 0

4 years ago

Read 2 more answers

Plugging in x back in the equation which is 6, what is the measure of this alternate exterior angle

andreyandreev [35.5K]

Answer:

14x - 4 + 13x + 2

= 14(6) - 4 + 13(6) + 2

= 160

5 0

3 years ago

SALES A daily newspaper had 12,125 subscribers when it began publication. Five years later it had 10,100 subscribers. What is th

vekshin1

Answer:

The average change is 405

Step-by-step explanation:

The initially the number of subscriber = 12125

After five years the number of subscriber = 10100

Now we have to find the average change in the number of subscribers.

The average yearly change = change in subscriber/number of years.

Now insert the values in the above formula.

The average yearly change = (12125 – 10100) / 5

The average yearly change = 2025/5

The average yearly change = 405

6 0

3 years ago

Sabendo que "K" satisfaz a equação {2(k-8) + 3(-k+1) = -4k +11} Os valores reais de x que satisfazem a equação 15x² - kx + 1 = 0

erastova [34]

Answer:

D) 1/5 e 1/3

Step-by-step explanation:

You have the following quadratic equation:

$15x^2-kx+1=0$ (1)

In order to find the values of x that are solution to the equation (1), you first find the solution for k in the following equation:

$2(k-8)+3(-k+1)=-4k+11\\\\2k-16-3k+3=-4k+11\\\\2k-3k+4k=11+16-3\\\\3k=24\\\\k=8$

Next, you replace the previous value of k in the equation (1) and you use the quadratic formula to find the roots:

$15x^2-8x+1=0\\\\x_{1,2}=\frac{-(-8)\pm \sqrt{(-8)^2-4(15)(1)}}{2(15)}\\\\x_{1,2}=\frac{8\pm 2}{30}\\\\x_1=\frac{1}{5}\\\\x_2=\frac{1}{3}$

Then, the roots of the equation (1) are

D) 1/5 e 1/3

5 0

4 years ago