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gavmur [86]
3 years ago
14

SALES A daily newspaper had 12,125 subscribers when it began publication. Five years later it had 10,100 subscribers. What is th

e average yearly rate of change in the number of subscribers for the five-year period?
Mathematics
1 answer:
vekshin13 years ago
6 0

Answer:

The average change is 405

Step-by-step explanation:

The initially the number of subscriber = 12125

After five years the number of subscriber = 10100

Now we have to find the average change in the number of subscribers.

The average yearly change = change in subscriber/number of years.

Now insert the values in the above formula.

The average yearly change = (12125 – 10100) / 5

The average yearly change = 2025/5

The average yearly change = 405

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Given:

x and y are both differentiable functions of t.

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To find:

The value of \dfrac{dx}{dt}.

Solution:

We have,

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At x=-1,

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3y^3=28-4

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Divide both sides by 3.

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Taking cube root on both sides.

y=2

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Differentiate (i) with respect to t.

4(2x\dfrac{dx}{dt})+3(3y^2\dfrac{dy}{dt})=0

Putting x=-1, y=2 and \dfrac{dy}{dt}=8, we get

4(2(-1)\dfrac{dx}{dt})+3(3(2)^28)=0

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-8(\dfrac{dx}{dt}-9(4))=0

Divide both sides by -8.

\dfrac{dx}{dt}-36=0

\dfrac{dx}{dt}=36

Therefore, the value of 4x^2+3y^3=28 is 36.

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Step-by-step explanation:

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