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gavmur [86]
3 years ago
14

SALES A daily newspaper had 12,125 subscribers when it began publication. Five years later it had 10,100 subscribers. What is th

e average yearly rate of change in the number of subscribers for the five-year period?
Mathematics
1 answer:
vekshin13 years ago
6 0

Answer:

The average change is 405

Step-by-step explanation:

The initially the number of subscriber = 12125

After five years the number of subscriber = 10100

Now we have to find the average change in the number of subscribers.

The average yearly change = change in subscriber/number of years.

Now insert the values in the above formula.

The average yearly change = (12125 – 10100) / 5

The average yearly change = 2025/5

The average yearly change = 405

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a fence 2.4m tall,is 10m away from a tree of height 16m.calculate the angle of elevation of the top of the tree from the top of
baherus [9]

Answer:

<em>53.67⁰</em>

Step-by-step explanation:

Give the height of the fence to be 2.4 m tall

Height of the tree = 16m

Horizintal distance from the fence to the tree = 10m

Check the diagram in the attachment.

From the attachment, we will need to first calculate the height AB

AC = AB+BC

Given AC = height of the r=tree = 16m

BC is the height of the fence = 2.4m

16 = AB + 2.4

AB = 16-2.4

AB = 13.6m

Using the SOH CAH TOA trig identity on right angled triangle AEB with AB as the opposite and AB and the adjacent as BE

Using TOA;

tan ∝ = opposite/adjacent = AB/BE

∝ is the angle of elevation of the top of the tree from the top of the fence​.

tan∝ = 13.6/10

tan∝ = 1.36

∝ = tan⁻¹1.36

∝ = 53.67⁰

<em>Hence the angle of elevation of the top of the tree from the top of the fence​ is 53.67⁰</em>

5 0
4 years ago
9. Find the missing value in the equation.<br> 3/4- blank/3=5/12
Goryan [66]

Answer:

\large\boxed{\dfrac{3}{4}-\dfrac{1}{3}=\dfrac{5}{12}}

Step-by-step explanation:

\dfrac{3}{4}-\dfrac{\boxed{\ }}{3}=\dfrac{5}{12}\\\\\bold{METHOD\ 1:}\\\\LCD=12\\\\\dfrac{3\cdot3}{4\cdot3}-\dfrac{4\cdot\boxed{\ }}{4\cdot3}=\dfrac{5}{12}\\\\\dfrac{9}{12}-\dfrac{4\boxed{\ }}{12}=\dfrac{5}{12}\\\\\dfrac{9-4\boxed{\ }}{12}=\dfrac{5}{12}\iff9-4\boxed{\ }=5\qquad\text{subtract 9 from both sides}\\\\-4\boxed{\ }=-4\qquad\text{divide both sides by (-4)}\\\\\boxed{\ }=1

\bold{METHOD\ 2:}\\\\\dfrac{3}{4}-\dfrac{\boxed{\ }}{3}=\dfrac{5}{12}\qquad\text{subtract}\ \dfrac{3}{4}\ \text{from both sides}\\\\-\dfrac{\boxed{\ }}{3}=\dfrac{5}{12}-\dfrac{3}{4}\\\\-\dfrac{\boxed{\ }}{3}=\dfrac{5}{12}-\dfrac{3\cdot3}{4\cdot3}\\\\-\dfrac{\boxed{}}{3}=\dfrac{5}{12}-\dfrac{9}{12}\\\\-\dfrac{\boxed{\ }}{3}=-\dfrac{4}{12}\\\\-\dfrac{\boxed{\ }}{3}=-\dfrac{1}{3}\to\boxed{\ }=1

5 0
4 years ago
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