Explain how a projectile might be modified to decrease the air resistance impacting its trajectory.
1 answer:
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Answer:
Explanation:
The equation that relates heat Q with the temperature change of a substance of mass <em>m </em>and specific heat <em>c </em>is
.
We want to calculate the final temperature <em>T, </em>so we have:
Which for our values means (in this case we do not need to convert the mass to Kg since <em>c</em> is given in g also and they cancel out, but we add to our temperature in
to have it in
as it must be):
Answer:
Both charges must have the same charge, Qt/2.
Explanation:
Let the two charges have charge Q1 and Q2, respectively.
Use Coulombs's Law to find an expression for the force between the two charges.
, where
Ke is Coulomb's contant and
r is the distance between the charges.
We know from the question that
Q1 + Q2 = Qt
So,
Q2 = Qt - Q1
Simplify to obtain,
In order to find the value of Q1 for which F is the maximum, we will use the optimization technique of calculus.
Differentiate F with respect to Q1,
Equate the differential to 0, to obtain the value of Q1 for which F is the maximum.
It follows that
.
Answer:
θ₂ = 40.5º
Explanation:
For this exercise we must use the law of refraction
n₁ sin θ₁ = n₂ sin θ₂
where index 1 is for the incident ray and index 2 is for the refracted ray
in this case the incident ray has an angle of θ₁ = 60º and the refractive index of the water is
n₂ = 1,333
sin θ₂ =
let's calculate
sin θ₂ = 1 / 1.3333 sin 60
sin θ₂ = 0.64968
θ₂ = sin⁻¹ (0.64968)
θ₂ = 40.5º