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Rashid [163]
3 years ago
13

A 4.0 g string, 0.36 m long, is under tension. The string produces a 500 Hz tone when it vibrates in the third harmonic. The spe

ed of sound in air is 344 m/s. In this situation, the wavelength of the standing wave in the string, in SI units, is closest to:
Physics
1 answer:
almond37 [142]3 years ago
5 0

Answer:

\lambda = 0.24 m

Explanation:

The string vibrates in the third harmonics, n = 3

Length of the string, l = 0.36 m

Frequency of the tone produced, f = 500 Hz

The speed of sound in air is 344 m/s

Calculate the speed of sound produced by the string in the third harmonics:

The frequency of sound is given by the formula:

f = \frac{nv}{2l} \\500 = \frac{3v}{2*0.36}\\500 * 2 * 0.36 = 3v\\v = 360/3\\v = 120 m/s\\v = \lambda f\\\lambda = v/f\\\lambda = 120/500\\\lambda = 0.24 m

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An engineering firm is designing a ski lift. The wire rope needs to travel with a linear velocity of 2.0 meters per second, and
Mazyrski [523]

Answer:

The diameter of the bull-wheel is 3.82

Explanation:

Given that,

Velocity = 2.0 m/s

Angular velocity = 10 rev/m

\omega=10\times\dfrac{2\pi}{60}

\omega=1.0472\ rad/s

We need to calculate the diameter of bull-wheel

Using formula of angular velocity

v= r\omega

r=\dfrac{v}{\omega}

Put the value into the formula

r=\dfrac{2.0}{1.0472}

r=1.91\ m

The diameter of the bull-wheel

D=2r

D=2\times1.91

D=3.82\ m

Hence, The diameter of the bull-wheel is 3.82 m.

6 0
3 years ago
an ice skater starts with a velocity of 2.25 m/s in a 50.0 direction. after 8.33 m/s in a 120 direction. what is the y-component
Nata [24]

The y-component of the acceleration is 0.28 m/s^2

Explanation:

The y-component of the ice skater acceleration can be calculated with the equation

a_y = \frac{v_y-u_y}{t}

where

v_y is the y-component of the final velocity

u_y is the y-component of the initial velocity

t is the time elapsed

Here we have:

  • Initial velocity is u=2.25 m/s at \theta_1=50.0^{\circ}, so its y-component is u_y = u sin \theta_1 = (2.25)(sin 50.0^{\circ})=1.72 m/s
  • Final velocity is v=4.65 m/s at \theta_2=120.0^{\circ}, so its y-component is v_y = v sin \theta_2 = (4.65)(sin 120.0^{\circ})=4.03 m/s

The time elapsed is

t = 8.33 s

Therefore, the y-component of the acceleration is

a_y = \frac{4.03-1.72}{8.33}=0.28 m/s^2

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7 0
3 years ago
Identify the solutions (homogeneous mixtures) in the list below. check all that apply. lead, an alloy of tin and lead ammonia, a
Goryan [66]

The solutions and homogeneous mixtures in the given list are:

A. Lead solder, an alloy of tin and lead.

D. Window cleaner, a mixture of ammonia and coloring dissolved in water.

E. Gasoline, a mixture of organic liquids with a fixed composition throughout.

<h3>What is a solution?</h3>

A solution can be defined as a special type of homogeneous mixture that comprises a solute and a solvent.

A homogeneous mixture can be defined as any solid, liquid, or gaseous mixture which has an identical (uniform) composition and properties throughout any given sample of the mixture.

In Science (Physics), all solutions are considered to be a homogeneous mixture because their constituents are uniformly (evenly) distributed.

In conclusion, the solutions and homogeneous mixtures in the given list are:

  • Lead solder, an alloy of tin and lead.
  • Window cleaner, a mixture of ammonia and coloring dissolved in water.
  • Gasoline, a mixture of organic liquids with a fixed composition throughout.

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4 0
2 years ago
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Two planes, which are 37403740 miles apart, fly toward each other. their speeds differ by 35mph35â¢mph. if they pass each other
Orlov [11]
33750 miles because it in the sky
5 0
3 years ago
In which of these star groups would you mostly likely find the least heavy-element abundance for the stars within them: open clu
djyliett [7]

Answer: globular clusters

Explanation:

A globular cluster is a star which is usually spherical, it’s a collection of stars which is known to orbits a galactic core. Globular clusters are usually very tightly bound together by gravity, this helps in giving them their spherical shapes which they are known for, and it’s relatively high stellar densities which is found toward their centers.

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