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Rashid [163]
3 years ago
13

A 4.0 g string, 0.36 m long, is under tension. The string produces a 500 Hz tone when it vibrates in the third harmonic. The spe

ed of sound in air is 344 m/s. In this situation, the wavelength of the standing wave in the string, in SI units, is closest to:
Physics
1 answer:
almond37 [142]3 years ago
5 0

Answer:

\lambda = 0.24 m

Explanation:

The string vibrates in the third harmonics, n = 3

Length of the string, l = 0.36 m

Frequency of the tone produced, f = 500 Hz

The speed of sound in air is 344 m/s

Calculate the speed of sound produced by the string in the third harmonics:

The frequency of sound is given by the formula:

f = \frac{nv}{2l} \\500 = \frac{3v}{2*0.36}\\500 * 2 * 0.36 = 3v\\v = 360/3\\v = 120 m/s\\v = \lambda f\\\lambda = v/f\\\lambda = 120/500\\\lambda = 0.24 m

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Answer:

The rise in height of combined block/bullet from its original position is 0.45m

Explanation:

Given;

mass of bullet, m₁ = 12 g = 0.012 kg

mass of block of wood, m₂ = 1 kg

initial speed of bullet, u₁ = 250 m/s.

initial speed of block of wood, u₂ = 0

From the principle of conservation of linear momentum, calculate the final speed of the combined block/bullet system.

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From the principle of conservation of energy, calculate the rise in height of the block/bullet combined from its original position.

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¹/₂v² = gh

¹/₂ (2.96)² = (9.8)h

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h = 4.3808/9.8

h = 0.45 m

Therefore, the rise in height of combined block/bullet from its original position is 0.45m

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