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weqwewe [10]
3 years ago
12

A girl on the beach sees 8 waves pass in 4 s. If the wavelength of each

Physics
2 answers:
kipiarov [429]3 years ago
8 0

Velocity = frequency x wavelength

              = \frac{8}{4} x 1.2

              = 0.6 m/s

fenix001 [56]3 years ago
5 0

Answer:

The velocity of wave is 2.4m/s.

Explanation:

First, find the frequency using the formula :

f =  \frac{1}{t}

Let t = 4,

f =  \frac{1}{4}

f = 0.25Hz

Next, given that each wave is 1.2m and there are 8 waves so the wavelength is :

λ = 1.2  \times 8

λ = 9.6m

Lastly, you have to use velocity formula :

v = f \times λ \:

Let f = 0.25Hz,

Let λ = 9.6m,

v = 0.25 \times 9.6

v = 2.4

(Correct me if I am wrong)

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A pendulum oscillates 12 times in 4 seconds. what is the length of the pendulum?
seraphim [82]

Answer:

L = 2.8 cm

Explanation:

Period T = 4 / 12 = 1/3 s

T = 2π√(L/g)

L = (T/2π)²g

L = ((1/3)/2π)²9.8 = 0.02758... ≈ 2.8 cm

6 0
2 years ago
A model rocket has an acceleration of 12 m/s2. A net force of 18 N is acting on the rocket. What is the mass of the rocket? its
larisa86 [58]

Answer:

C.) 1.5 kg

Explanation:

Start with the equation:

F_n_e_t=ma

Plug in what you know, and solve:

18=m(12)\\m=1.5kg

Find matching soluation:

C.) 1.5 kg

5 0
2 years ago
What are the characteristics of high energy waves?
sladkih [1.3K]
<span>The relationship between wavelength, frequency and energy of Electromagnetic Radiation is given by E = hf = hc/lamba -------(1) So from (1) there's a linear relationship between E and f. The higher the frequency, f, the higher the energy E. Also from (1) it is obvious that the lower the wavelength, lambda, the higher the energy, E. This means the answer is D.</span>
4 0
3 years ago
Read 2 more answers
Example 3 :
kherson [118]

The friction factor and head loss when velocity is 1m/s is 0.289 and 1.80 × 10^8 respectively. Also, the friction factor and head loss when velocity is 3m/s is 0.096 and 5.3 × 10^8 respectively.

<h3>How to determine the friction factor</h3>

Using the formula

μ = viscosity = 0. 06 Pas

d =  diameter = 120mm = 0. 12m

V =  velocity = 1m/s and 3m/s

ρ = density = 0.9

a. Velocity = 1m/s

friction factor = 0. 52 × \frac{0. 06}{0. 12* 1* 0. 9}

friction factor = 0. 52 × \frac{0. 06}{0. 108}

friction factor = 0. 52 × 0. 55

friction factor = 0. 289

b. When V = 3mls

Friction factor = 0. 52 × \frac{0. 06}{0. 12 * 3* 0. 9}

Friction factor = 0. 52 × \frac{0. 06}{0. 324}

Friction factor = 0. 52 × 0. 185

Friction factor = 0.096

Loss When V = 1m/s

Head loss/ length = friction factor × 1/ 2g × velocity^2/ diameter

Head loss = 0. 289 × \frac{1}{2*6. 6743 * 10^-11} × \frac{1^2}{0. 120} × \frac{1}{100}

Head loss =  1. 80 × 10^8

Head loss When V = 3m/s

Head loss = 0. 096 × \frac{1}{1. 334 *10^-10} × \frac{3^2}{0. 120} × \frac{1}{100}

Head loss = 5. 3× 10^8

Thus, the friction factor and head loss when velocity is 1m/s is 0.289 and 1.80 ×10^8 respectively also, the friction factor and head loss  when velocity is 3m/s is 0.096 and 5.3 ×10^8 respectively.

Learn more about friction here:

brainly.com/question/24338873

#SPJ1

4 0
1 year ago
In order to simulate weightlessness for astronauts in training, they are flown in a vertical circle. if the passengers are to ex
sleet_krkn [62]
The answer is "156.6 m/s".

This is how we calculate this;

-N + mg = ma = mv²/r

For "weightlessness" N = 0, so

0 = mg - mv²/r 

g - v²/r = 0 

v =√( gr)
g = 9.8 and r = 2.5km = 2500 m

v = √(9.8 x 2500)

= 156.6 m/s
8 0
3 years ago
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