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weqwewe [10]
3 years ago
12

A girl on the beach sees 8 waves pass in 4 s. If the wavelength of each

Physics
2 answers:
kipiarov [429]3 years ago
8 0

Velocity = frequency x wavelength

              = \frac{8}{4} x 1.2

              = 0.6 m/s

fenix001 [56]3 years ago
5 0

Answer:

The velocity of wave is 2.4m/s.

Explanation:

First, find the frequency using the formula :

f =  \frac{1}{t}

Let t = 4,

f =  \frac{1}{4}

f = 0.25Hz

Next, given that each wave is 1.2m and there are 8 waves so the wavelength is :

λ = 1.2  \times 8

λ = 9.6m

Lastly, you have to use velocity formula :

v = f \times λ \:

Let f = 0.25Hz,

Let λ = 9.6m,

v = 0.25 \times 9.6

v = 2.4

(Correct me if I am wrong)

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The drawing shows two situations in which charges are placed on the x and y axes. They are all located at the same distance of 5
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= 7.88e6(x) + 7.88e6(y)

use Pythagorean theorem

I <em>E </em>I  = \sqrt{(7.89e5)^{2}  + (7.89e5)^{2}} =  1.242e6\frac{N}{C}

∅ = tan^{-1}(\frac{7.88e5}{7.88e5} ) = tan^{-1}(1) = 45°

Thus for (a) net magnitude =  1.115e6\frac{N}{C} @ 45° above +x axis

for situation (b)

net charge E = E₊₄ + E₊₁ + E₋₁ + E₊₆

E₊₄(x) = K(q/d²) = (8.99e9)× ((4.0e-6)÷(5.7e-2)) = 6.30e5(+x)

 E₊₁(y) = K(q/d²) = (8.99e9)× ((1.0e-6)÷(5.7e-2)) = 1.58e5(-y)

E₋₁(x) = K(q/d²) = (8.99e9)× ((1.0e-6)÷(5.7e-2)) = 1.58e5(+x)

E₊₆(y) = K(q/d²) = (8.99e9)× ((6.0e-6)÷(5.7e-2)) = 9.46e5(+y)

thus,

E = E₊₄ + E₊₁ + E₋₁ + E₊₆

= 6.30e5(x) - 1.58e5(y) + 1.58e5(x) + 9.46e5(y)

= 7.88e5(x) + 7.88e5(y)

use Pythagorean theorem

I <em>E </em>I  = \sqrt{(7.88e5)^{2}  + (7.88e5)^{2}} =  1.242e6\frac{N}{C}

∅ = tan^{-1}(\frac{7.88e5}{7.88e5} ) = tan^{-1}(1) = 45°

Thus for (a) and (b) the net magnitude =  1.242e6\frac{N}{C} @ 45° above +x axis

Explanation:

I attached a sample image, i hope that corresponds to your question

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