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weqwewe [10]
3 years ago
12

A girl on the beach sees 8 waves pass in 4 s. If the wavelength of each

Physics
2 answers:
kipiarov [429]3 years ago
8 0

Velocity = frequency x wavelength

              = \frac{8}{4} x 1.2

              = 0.6 m/s

fenix001 [56]3 years ago
5 0

Answer:

The velocity of wave is 2.4m/s.

Explanation:

First, find the frequency using the formula :

f =  \frac{1}{t}

Let t = 4,

f =  \frac{1}{4}

f = 0.25Hz

Next, given that each wave is 1.2m and there are 8 waves so the wavelength is :

λ = 1.2  \times 8

λ = 9.6m

Lastly, you have to use velocity formula :

v = f \times λ \:

Let f = 0.25Hz,

Let λ = 9.6m,

v = 0.25 \times 9.6

v = 2.4

(Correct me if I am wrong)

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Which is gerrymandering a problem for the house of representatives but not the senate?
Fudgin [204]

Senators are elected in statewide elections rather than in specific districts. <em>(D)</em>

3 0
3 years ago
Which subatomic particle has the smallest mass?
spin [16.1K]

Answer:

quark

Explanation:

neutrón= 1.675 x 10-27 kg

proton=1,673 x 10-27 kg

electron=9,11 x 10-31 kg

quark=7,13 - 14,26 · 10−30 kg

3 0
2 years ago
What is the voltage in a circuit that has a current of 10.0 amps and a resistance of 28.5 ohms?
marin [14]
Voltage = Current (I) × Resistance (R)
V = 10 × 28.5 = 285v
6 0
4 years ago
On a hot day, the temperature of a 65,000-L swimming pool increases by 1.20°C. What is the net heat transfer during this heating
vichka [17]

Answer:

326149.2 KJ

Explanation:

The heat transfer toward and object that suffered an increase in temperature can be calculated using the expression:

Q = m*cv*ΔT

Where m is the mass of the object, cv is the specific heat capacity at constant volume, which basically means the amount of heat necessary for a 1kg of water to increase 1C degree in temperatur, and ΔT is the change in temperature.

A 65000 L swimming pool will have a mass of:

65000L *\frac{1m^3}{1000L} * \frac{1000kg}{1m^3} = 65000 kg

The specific heat capacity at constant volume of water is equal to 4.1814 KJ/KgC.

We replace the data and get:

Q = m*cv*ΔT = 65000 kg * 4.1814 KJ/KgC * 1.2°C = 326149.2 KJ

3 0
3 years ago
Suppose that a teacher driving a 1972 LeMans zooms out of a darkened tunnel at 34.5 m/s. He is momentarily blinded by the sunshi
valkas [14]

Answer:

489.19m

Explanation:

To find the minimum distance you first calculate the time in which the teacher stops:

v=v_o-at\\\\t=\frac{v_o-v}{a}=\frac{34.5m/s-0m/s}{2.5m/s^2}=13.8s

however, the reaction of the teacher is 0.31s later, then you use

t=13.8-0.31s=13.49s

during this time the camper has traveled a distance of:

x=vt=(15.1m/s)(13.49s)=203.69m   (1)

Next you calculate the distance that teacher has traveled for 13.6s:

x=x_o+v_ot+\frac{1}{2}at^2\\\\x=0m+34.5m/s(13.49s)+\frac{1}{2}(2.5m/s^2)(13.49s)^2=692.88m  (2)

The minimum distance between the driver and the camper will be the difference between (2) and (1):

x_{min}=692.88m-203.69m=489.19m

5 0
3 years ago
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