An envelope is 6 in. wide and 4 in. high. Will a card with an 8 in. diagonal fit in it? Identify the correct explanation.

1 answer:

5 0

First we have to find the diagonal of the card. We do this by using the Pythagoras theorem: A^2 = b^2 + c^2
= 6^2 + 4^2
=36 + 16
= 52
A^2= 52
Sqrt A^2 = sqrt 52
A = 7.2
Since the envelopes diagonal is 7.2 inches and the card’s diagonal is 8 inches and 7.2<8. Your answer is c)

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blsea [12.9K]

Answer:

419 ft

Step-by-step explanation:

1063 ft is about 324002.4 mm

324002.4/477 to get the scale ratio. Which is 679.25:1

I am halfway through the problem and notice I should have converted mm to ft and not the other way around. It gives the same answer it just takes an extra step.

188*679.25=127699mm for one side.

Convert that back to ft and you get 418.959 which would just be 419 ft

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3 years ago

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Vanyuwa [196]

Answer: 3/2

Step-by-step explanation:

Let's consider the points (6,9) and (4,6).

The difference in the y coordinates is 3, and the diffeence in the x coordinates is 2.

So, the slope is 3/2.