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Keith_Richards [23]

3 years ago

8

An envelope is 6 in. wide and 4 in. high. Will a card with an 8 in. diagonal fit in it? Identify the correct explanation.

1 answer:

lisov135 [29]3 years ago

5 0

First we have to find the diagonal of the card. We do this by using the Pythagoras theorem: A^2 = b^2 + c^2
= 6^2 + 4^2
=36 + 16
= 52
A^2= 52
Sqrt A^2 = sqrt 52
A = 7.2
Since the envelopes diagonal is 7.2 inches and the card’s diagonal is 8 inches and 7.2<8. Your answer is c)

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