Answer:
22.459 pounds of wood
Step-by-step explanation:
Total amount of wood in store = amount of pine wood purchased + amount of cedar in the store
Total amount of wood in store = 13.145 pine wood + 16.903 cedar wood
Total amount of wood in store = 30.048 pounds of wood
If acme lumber had sold 7.589 pounds of lumber after 6 months, the amount of pounds of woods that the company have left to sell = Total amount in store initially - amount sold after 6 months
Amount of pounds of woods that the company have left to sell = 30.048 - 7.589
The amount of pounds of woods that the company have left to sell = 22.459 pounds of wood
Answer:
B. A teacher compares the pre-test and post-test scores of students
Step-by-step explanation:
the answer is true, because it is a good example to compare the tests between students, we know that a matching pair design is a random model and is used when the experiment allows grouping subjects in pairs based on a variable and each pair will receive randomly a different handling, the answer A is not true because in the example all students are uniformly averaged and the variable is not correlated with subgroups, option c is incorrect because the variable was not randomized and generates classification bias and the option d is incorrect because the teacher compares a small sample as her class with a score of a total sample, but does not intervene on her students when selecting the corresponding group
99 is the biggest 2 digit number correct? So 1000 more than that is 99 + 1000 = 1099
Answer:
0.2008 = 20.08% probability that among 150 calls received by the switchboard, there are at least two wrong numbers.
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:
In which
x is the number of sucesses
e = 2.71828 is the Euler number
is the mean in the given interval.
The probability that a call received by a certain switchboard will be a wrong number is 0.02.
150 calls. So:
Use the Poisson distribution to approximate the probability that among 150 calls received by the switchboard, there are at least two wrong numbers.
Either there are less than two calls from wrong numbers, or there are at least two calls from wrong numbers. The sum of the probabilities of these events is 1. So
We want to find 
. So
In which
Then
0.2008 = 20.08% probability that among 150 calls received by the switchboard, there are at least two wrong numbers.
