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alexgriva [62]
2 years ago
6

PLEASE HELP GIVING BRAINLIEST

Mathematics
1 answer:
77julia77 [94]2 years ago
3 0

Answer:

The answer is A)

Step-by-step explanation:

When the plane length increases, the force required gets reduced while the plane height stays the same.

<em>Hope this helps!</em>

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Answer:

3r + 4t = 80

Step-by-step explanation:

Roses cost $3 each, tulips cost $4 each

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My god, this is tricky but it's between D and E. 

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4 years ago
On a coordinate plane, a curved line with a minimum value of (negative 1.25, negative 3.25) and a maximum value of (0.25, negati
Juliette [100K]

The correct option is:

As the x-values go to positive infinity, the function's values go to positive infinity.

<h3>What is the end behavior of the function?</h3>

By the description, We know that the function has the points:

(-1.25, -3.25), (0.25, -1.75) (-2.25, 0), (0, -2), (-2.75, 6), (1.5, 6)

Notice that from x = 0.25 to x = 1.5 the function goes upwards, then in the right side, the function goes up, so as x goes to positive infinity, also does f(x).

On the left side, we can see  that from x = -2.75 to x = -2.25 the function goes downwards.

So, as x goes to the left (negative infinity) f(x) goes upwards.

Then as x tends to negative infinity, f(x) tends to infinity.

The correct option is:

As the x-values go to positive infinity, the function's values go to positive infinity.

If you want to learn more about end behavior:

brainly.com/question/1365136

#SPJ1

8 0
2 years ago
Use the properties of exponents to rewrite the expression.<br> (-3yz)(-3yz)(-3yz)(-3yz)
Lera25 [3.4K]

Answer:

Answer is 81y^4z^4

Step-by-step explanation:

The expression is (-3yz) (-3yz) (-3yz) (-3yz).

Since all the four terms have power 1:

(-3yz)^1 (-3yz)^1 (-3yz)^1 (-3yz)^1

We know that we can add the powers if the terms have same base

So,

=(-3yz)^1+1+1+1

=(-3yz)^4

=(-3)^4(y)^4(z)^4.

If the power is an even number than the negative sign changes into positive sign.

=3^4y^4z^4

=81y^4z^4

Thus the answer is 81y^4z^4....

3 0
3 years ago
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