GIVEN :
a = 1/√10 ( 3i + k) and
b = 1/7 ( 2i + 3j - 6k)
TO FIND :
( 2a- b) . [ ( a x b ) x ( a + 2b)]
SOLUTION :
◆Going with the equation given,
( 2a - b) . [ ( a x b ) x ( a + 2b)]
= (2a - b) [( a×b×a) + 2(a×b)×b]
◆BAC - CAB RULE,
A×B×C = B( A.B ) - C(A.B )
= (2a- b ) [ (b (a.a ) - a (a.b ) + 2b ( a.b) -2b (a.b]
Solving further
= (2a - b )(b - 2a)
= -4a.a -b.b
=-5.
Answer:
( 2 - b) . [ ( a x b ) x ( a + 2b)] = -5
Hoped I helped
Using the Pythagorean Theorem,
radius^2 = 40^2 + 9^2
radius^2 = 1,600 + 81
radius^2 = 1,681
radius = 41
Answer:
792
Step-by-step explanation:
Are theese questions or your answers
if there answers they seem all right
Answer:
Step-by-step explanation:
<u>Alexis spends:</u>
- $8.50 + $7.25 + $5 = $20.75
<u>Money left:</u>
