You would make all the fractions have the same common denominator of 12. First you would keep the fraction 7/12 because the denominator is already 12. Next you would take the fraction 1/3 and multiply it by 4/4 and the new fraction for 1/3 becomes 4/12. Lastly you would take 2/3 and multiply that by 4/4 and the fraction becomes 8/12. Now you can compare the fractions with the same denominator. Therefore 7/12 is greater than 1/3 but less than 2/3
Answer:
-1
Step-by-step explanation:
We can find the slope by change in y of change in x
change in y
---------------------
change in x
The y changes -3 ( goes down 3)
the x changes +3 ( to the right 3)
-3
----
3
This simplifies to -1
Answer:
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Answer:
60cm^2
Step-by-step explanation:
We assume that is a circumscribing quadrilateral, rather than one that is circumscribed. It is also called a "tangential quadrilateral" and its area is ...
K = sr
where s is the semi-perimeter, the sum of opposite sides, and r is the radius of the incircle.
K = (12 cm) (5cm) = 60 cm²
_____
A quadrilateral can only be tangential if pairs of opposite sides add to the same length. Hence the given sum is the semiperimeter.
You haven't provided the required roots, but I can tell you how to do this kind of exercises in general.
If the 
coefficient is 1, i.e. the equation is written like 
, then you can say the following about the coefficients b and c:
is the opposite of the sum of the roots
is the multiplication of the roots.
So, for example, if we want an equation whose roots are 4 and -2, we have:
So, the equation is 
If your roots are rational, you can work like this: suppose you want an equation with roots 3/4 and 1/2. You have:
And so the equation is
In order to have integer coefficients, you can multiply both sides of the equation by 8:
