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zzz [600]
3 years ago
15

A

Mathematics
1 answer:
Westkost [7]3 years ago
3 0

Answer:

he would do 9 weeks of school

Step-by-step explanation:

count by fives

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Explain how you know that 7/12 is greater than 1/3 but less t than 2/3
Dmitrij [34]
You would make all the fractions have the same common denominator of 12. First you would keep the fraction 7/12 because the denominator is already 12. Next you would take the fraction 1/3 and multiply it by 4/4 and the new fraction for 1/3 becomes 4/12. Lastly you would take 2/3 and multiply that by 4/4 and the fraction becomes 8/12. Now you can compare the fractions with the same denominator. Therefore 7/12 is greater than 1/3 but less than 2/3 

8 0
3 years ago
What is the slope below
raketka [301]

Answer:

-1

Step-by-step explanation:

We can find the slope by change in y of change in x

change in y

---------------------

change in x

The y changes  -3  ( goes down 3)

the x changes +3 ( to the right 3)

-3

----

3

This simplifies to -1

4 0
3 years ago
Read 2 more answers
If P = (-1,6), Find: Rx-axis (P).
Hatshy [7]

Answer:

fufh idjd j djj bcixbcjdbxjx. jx. he. jj FHA g j y j hh j y hcj hy h jejdjd j. djxjj. sndj j. djdjjd. cjdjdj. jdjjdjd. jdjdjd j jdjdjjejejd dkdjdjhdjsjjd

7 0
3 years ago
Read 2 more answers
The sum of the lengths of two opposite sides of the circumscribed quadrilateral is 12 cm, the length of a radius of the circle i
nasty-shy [4]

Answer:

60cm^2

Step-by-step explanation:

We assume that is a circumscribing quadrilateral, rather than one that is circumscribed. It is also called a "tangential quadrilateral" and its area is ...

 K = sr

where s is the semi-perimeter, the sum of opposite sides, and r is the radius of the incircle.

 K = (12 cm) (5cm) = 60 cm²

_____

A quadrilateral can only be tangential if pairs of opposite sides add to the same length. Hence the given sum is the semiperimeter.

8 0
3 years ago
Write a quadratic equation with the given roots. Write the equation in the form of ax^2+bx+c=0 where a b and c are integers
Bas_tet [7]

You haven't provided the required roots, but I can tell you how to do this kind of exercises in general.

If the x^2 coefficient is 1, i.e. the equation is written like x^2+bx+c=0, then you can say the following about the coefficients b and c:

  • b is the opposite of the sum of the roots
  • c is the multiplication of the roots.

So, for example, if we want an equation whose roots are 4 and -2, we have:

  • 4+(-2) = 4-2 = 2 \implies b = -2
  • 4 \cdot (-2) = -8 \implies c = -8

So, the equation is x^2-2x-8=0

If your roots are rational, you can work like this: suppose you want an equation with roots 3/4 and 1/2. You have:

  • \dfrac{3}{4}+\dfrac{1}{2} = \dfrac{3}{4}+\dfrac{2}{4} = \dfrac{5}{4} \implies b = -\dfrac{5}{4}
  • \dfrac{3}{4} \cdot \dfrac{1}{2} = \dfrac{3}{8} \implies c = \dfrac{3}{8}

And so the equation is

x^2 - \dfrac{5}{4} + \dfrac{3}{8} = 0

In order to have integer coefficients, you can multiply both sides of the equation by 8:

8x^2 - 10 + 3 = 0

5 0
3 years ago
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