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Nostrana [21]
3 years ago
8

Polimerlerin su ile parçalanarak monomerlerine ayrılmasına ne denir?​

Mathematics
1 answer:
kolbaska11 [484]3 years ago
5 0

Answer:

tarlak iefdiebdid didbdkd

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Work out 3√−64<br> the 3 is small ( cubed )
Alekssandra [29.7K]

3√-64 = -4

The answer is -4.

7 0
3 years ago
Which distance measures 5 units?
beks73 [17]

Answer:

B

Step-by-step explanation:

The distance between point x and y

6 0
3 years ago
Maria y juan deben realizar el mapamundi en medio pliego de cartulina para la tarea de sociales pero cada uno tiene un cuarto de
kondor19780726 [428]

Answer:

Cuando María afirma que si unen sus dos cuartos de cartulina obtendrán el medio pliego que necesitan, esto es:

  • <u>Verdadero</u>.

Step-by-step explanation:

Para entender mejor el ejercicio vamos a utilizar números cada vez que se habla de cantidades de cartulina, por lo tanto, María y Juan tienen 1/4 de cartulina cada uno, es decir, 1/4 * 2, y necesitan 1/2 pliego para poder realizar su tarea, por lo tanto, con la afirmación de María sobre unir los dos cuartos de cartulina, en caso de que sea verdadero, ocurrirá que la suma de los dos cuartos dará el medio pliego, como se muestra a continuación:

  • Total de cartulina de María y Juan = \frac{1}{4}+\frac{1}{4}
  • Total de cartulina de María y Juan = \frac{4+4}{16}
  • Total de cartulina de María y Juan = \frac{8}{16}

Procedemos a simplificar el fraccionario obtenido, sacando mitad tanto en el numerador como en el denominador:

  • Total de cartulina de María y Juan = \frac{4}{8}
  • Total de cartulina de María y Juan = \frac{2}{4}
  • <u><em>Total de cartulina de María y Juan = </em></u>\frac{1}{2}<u><em /></u>

Como puedes ver al final, <u>la cantidad de cartulina de ambos, al ser sumada, da como resultado el 1/2 (medio) pliego que necesitan para su tarea de sociales, por lo cual la afirmación de María es correcta</u>.

3 0
3 years ago
Suppose m = 2 + 6i, and | m + n | = 3√10, where n is a complex number.
Ksju [112]

Answer: a) √50

b) n = 1 + 7i

Step-by-step explanation:

first, the modulus of a complex number z = a + bi is

IzI = √(a^2 + b^2)  

The fact that n is complex does not mean that n doesn't has a real part, so we must write our numbers as:

m = 2 + 6i

n = a  + bi

Im + nI = 3√10

Im + n I = √(a^2 + b^2 + 2^2 + 6^2)= 3√10

            = √(a^2 + b^2 + 40) = 3√10

             a^2 + b^2 + 40 = 3^2*10 = 9*10 = 90

             a^2 + b^2 = 90 - 40 = 50

            √(a^2 + b^2 ) = InI = √50

The modulus of n must be equal to the square root of 50.

now we can find any values a and b such a^2 + b^2 = 50.

for example, a = 1 and b = 7

1^2 + 7^2 = 1 + 49  = 50

Then a possible value for n is:

n = 1 + 7i

6 0
3 years ago
Explain how to determine whether a point is a solution to a linear inequality?
Orlov [11]

Answer:The solution of a linear inequality in two variables like Ax + By > C is an ordered pair (x, y) that produces a true statement when the values of x and y are substituted into the inequality.

Example

Is (1, 2) a solution to the inequality

2x+3y>1

2⋅1+3⋅2>?1

2+5>?1

7>1

The graph of an inequality in two variables is the set of points that represents all solutions to the inequality. A linear inequality divides the coordinate plane into two halves by a boundary line where one half represents the solutions of the inequality. The boundary line is dashed for > and < and solid for ≤ and ≥. The half-plane that is a solution to the inequality is usually shaded.

Step-by-step explanation:

5 0
3 years ago
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