With
defined by

in order for it to be continuous at
, we require

(i) If
and
, then
and


The limits don't match, so
is not continuous at
under these conditions.
(ii) To establish continuity at
, we'd need the limit as
from the right to be equal to the limit from the left, or

(iii) We have
and


For
to be continuous at
, then, we'd need to have

(iv) Taking both requirements from parts (ii) and (iii), we solve for
:

I've attached a plot that confirms this is correct.
Answer:
4 - 3r
Step-by-step explanation:
D is just a statement of words, completely unrelated to math. C is an equation since because of the product and equal sign. hope that makes sense.
Answer:
10.9
Step-by-step explanation:
Pythagoras theorem- a² + b² = c²
Since this is a right angle with each side on the right angle's length given you can use pythagoras theorem.
7² + 8.44² = c²
= 49 + 70.56 = c²
= 119.56 = c²
∴ c = √119.56
= 10.9
Answer:
A ) Substitute the side lengths of a and b in the equation
Step-by-step explanation:
The hypotenuse which is opposite the right angle it always the length of C in the cosine rule.
Answer:
Because they are parrallel you already know that whatever the answer is, the slopes are the same