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Elza [17]
2 years ago
11

Which of the following would be an acceptable first step in simplifying the expression tanx/1+ secx

Mathematics
2 answers:
djverab [1.8K]2 years ago
4 0

The acceptable first step in simplifying the expression \mathbf{\frac{tan\ x}{1 + sec\ x}} is (a) \mathbf{\frac{tan\ x(1 - sec\ x)}{(1 + sec\ x)(1 - sec\ x)}}

The expression is given as:

\mathbf{\frac{tan\ x}{1 + sec\ x}}

To change the form of the expression, we simply perform several arithmetic operations on it.

Start by multiplying the expression by 1/1

\mathbf{\frac{tan\ x}{1 + sec\ x} = \frac{tan\ x}{1 + sec\ x} \times \frac 11}

Express 1 /1 as (1 - sec x)/(1 - sec x)

\mathbf{\frac{tan\ x}{1 + sec\ x} = \frac{tan\ x}{1 + sec\ x} \times \frac{1 - sec\ x}{1 - sec\ x}}

Rewrite the above expression as follows:

\mathbf{\frac{tan\ x}{1 + sec\ x} = \frac{tan\ x(1 - sec\ x)}{(1 + sec\ x)(1 - sec\ x)}}

Hence, the acceptable first step is (a)

Read more about trigonometry ratios at:

brainly.com/question/24888715

Tresset [83]2 years ago
3 0

Answer:

A

Step-by-step explanation:

The possible first step is A

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Solve by completing the square. Round your answers to the nearest tenth and then locate the greater solution. <img src="https://
Andrews [41]

Step-by-step explanation:

Step 1: Write our Givens

{x}^{2}  + 10x - 7 = 0

Move the constant term ,(the term with no variable) to the right side.

Here we have a negative 7, so we add 7 to both sides

{x}^{2}  + 10x = 7

Next, we take the linear coeffeicent and divide it by 2 then square it.

( \frac{10}{2} ) {}^{2}  = 25

Then we add that to both sides

{x}^{2}  + 10x + 25 = 7 + 25

{ {x}^{2} } + 10x + 25 = 32

Next, we factor the left,

(x + 5)(x + 5) = 32

we got 5 because 5 add to 10 and multiply to 25 as well.

so we get

(x + 5) {}^{2}  = 32

This is called a perfect square trinomial.

Next, we take the square root of both sides

x + 5 = ± \sqrt{32}

± menas that we have a positive and negative solution.

Subtract 5 form both side so we get

x =  - 5± \sqrt{32}

The greater solution is when sqr root of 32 is positive so the answer to that is

\sqrt{32}  - 5 = 0.7

3 0
2 years ago
In ΔIJK, k = 57 inches, i = 37 inches and ∠J=141°. Find ∠I, to the nearest degree.
Sonbull [250]

Answer:

<I= 15degrees

Step-by-step explanation:

Using the cosine rule formulae;

j² = i²+k²-2i cos <J

j² = 37²+57² - 2(37)(57)cos <141

j² = 1369+ 3249- 4218cos <141

j² = 4618- 4218cos <141

j² = 4618-(-3,278)

j²= 7,896

j = √7,896

j = 88.86inches

Next is to get <I

i² = j²+k²-2jk cos <I

37² = 88.86²+57² - 2(88.86)(57)cos <I

1369 = 7,896.0996+ 3249- 10,130.04cos <I

1369 = 11,145.0996 - 10,130.04cos <I

1369 - 11,145.0996 = - 10,130.04cos <I

-9,776.0996=- 10,130.04cos <I

cos <I =9,776.0996 /10,130.04

cos<I = 0.96506

<I = 15.19

<I= 15degrees

8 0
3 years ago
Rewrite the following equation in logarithmic form.
zloy xaker [14]

Answer:

log2(0.25) = -2

512 = 8^3

Step-by-step explanation:

  • <em>Use of formula: </em><em>loga (b) = c ⇔ b = a^c</em>

Rewrite the following equation in logarithmic form.   0.25 = 2^-2

  • log2(0.25) = -2

Rewrite the following equation in exponential form.  log8 (512) = 3

  • 512 = 8^3
3 0
3 years ago
A garden in the shape of trapezoid has an area of 44.4 square meters. One base is 4.3 meters long and the other base is 10.5 met
mamaluj [8]

Answer:

22.5 1/2

Step-by-step explanation:

4 0
4 years ago
Can anybody help with this? Please!!
ArbitrLikvidat [17]
Cos is the adjacent (side next to the angle in question) divided by the hypotenuse (sloped side)
for angle K, this is therefore 7/25
5 0
3 years ago
Read 2 more answers
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