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Elza [17]
2 years ago
11

Which of the following would be an acceptable first step in simplifying the expression tanx/1+ secx

Mathematics
2 answers:
djverab [1.8K]2 years ago
4 0

The acceptable first step in simplifying the expression \mathbf{\frac{tan\ x}{1 + sec\ x}} is (a) \mathbf{\frac{tan\ x(1 - sec\ x)}{(1 + sec\ x)(1 - sec\ x)}}

The expression is given as:

\mathbf{\frac{tan\ x}{1 + sec\ x}}

To change the form of the expression, we simply perform several arithmetic operations on it.

Start by multiplying the expression by 1/1

\mathbf{\frac{tan\ x}{1 + sec\ x} = \frac{tan\ x}{1 + sec\ x} \times \frac 11}

Express 1 /1 as (1 - sec x)/(1 - sec x)

\mathbf{\frac{tan\ x}{1 + sec\ x} = \frac{tan\ x}{1 + sec\ x} \times \frac{1 - sec\ x}{1 - sec\ x}}

Rewrite the above expression as follows:

\mathbf{\frac{tan\ x}{1 + sec\ x} = \frac{tan\ x(1 - sec\ x)}{(1 + sec\ x)(1 - sec\ x)}}

Hence, the acceptable first step is (a)

Read more about trigonometry ratios at:

brainly.com/question/24888715

Tresset [83]2 years ago
3 0

Answer:

A

Step-by-step explanation:

The possible first step is A

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Alchen [17]

Answer:

26

Step-by-step explanation:

f(x)=x^2+5x g(x)=5‒x

f(3)=3^2+5(3) g(3)=5‒3

f(3)=9+15 g(3)=2

f(3)=24

f(3)+g(3)=24+2

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6 0
3 years ago
Write the word phrases into an algebraic expression : 4 less than 5 times a number "p"
shusha [124]
Answer: 5p - 4

5 times ‘p’ = 5p
4 less than ‘p’ = p - 4

Therefore,
=> 5p - 4
4 0
1 year ago
Someone help me with this. I forgot my notes in class
Nonamiya [84]

Answer:

see explanation

Step-by-step explanation:

Since AB = BC the the triangle is isosceles and thus

∠ A = ∠ C = 8x

The sum of the 3 angles in a triangle = 180°

Sum the 3 angles and equate to 180

44x + 8x + 8x = 180, that is

60x = 180 ( divide both sides by 60 )

x = 3

Thus

∠ A = ∠ C = 8x = 8(3) = 24°

∠ B = 44x = 44(3) = 132°

6 0
2 years ago
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Find the area of the region enclosed by the graphs of the functions
Vaselesa [24]

Answer:

\displaystyle A = \frac{8}{21}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

<u>Algebra I</u>

  • Terms/Coefficients
  • Functions
  • Function Notation
  • Graphing
  • Solving systems of equations

<u>Calculus</u>

Area - Integrals

Integration Rule [Reverse Power Rule]:                                                                 \displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C

Integration Rule [Fundamental Theorem of Calculus 1]:                                      \displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)

Integration Property [Addition/Subtraction]:                                                          \displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx

Area of a Region Formula:                                                                                     \displaystyle A = \int\limits^b_a {[f(x) - g(x)]} \, dx

Step-by-step explanation:

*Note:

<em>Remember that for the Area of a Region, it is top function minus bottom function.</em>

<u />

<u>Step 1: Define</u>

f(x) = x²

g(x) = x⁶

Bounded (Partitioned) by x-axis

<u>Step 2: Identify Bounds of Integration</u>

<em>Find where the functions intersect (x-values) to determine the bounds of integration.</em>

Simply graph the functions to see where the functions intersect (See Graph Attachment).

Interval: [-1, 1]

Lower bound: -1

Upper Bound: 1

<u>Step 3: Find Area of Region</u>

<em>Integration</em>

  1. Substitute in variables [Area of a Region Formula]:                                     \displaystyle A = \int\limits^1_{-1} {[x^2 - x^6]} \, dx
  2. [Area] Rewrite [Integration Property - Subtraction]:                                     \displaystyle A = \int\limits^1_{-1} {x^2} \, dx - \int\limits^1_{-1} {x^6} \, dx
  3. [Area] Integrate [Integration Rule - Reverse Power Rule]:                           \displaystyle A = \frac{x^3}{3} \bigg| \limit^1_{-1} - \frac{x^7}{7} \bigg| \limit^1_{-1}
  4. [Area] Evaluate [Integration Rule - FTC 1]:                                                    \displaystyle A = \frac{2}{3} - \frac{2}{7}
  5. [Area] Subtract:                                                                                               \displaystyle A = \frac{8}{21}

Topic: AP Calculus AB/BC (Calculus I/II)  

Unit: Area Under the Curve - Area of a Region (Integration)  

Book: College Calculus 10e

6 0
2 years ago
What is 24÷8 &gt;jhhh4hg4h55h5gt5hh5
stealth61 [152]
The answer is 3

Hhhhhhh
4 0
3 years ago
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