The answer is log3 k to the seventh power m to the sixth power over n to the ninth power
a * logₓ(y) = logₓ(yᵃ)
7 log₃ (k) = log₃ (k⁷)
6 log₃ (m) = log₃ (m⁶)
9 log₃ (n) = log₃ (n⁹)
7 log₃ (k) + 6 log₃ (m) - 9 log₃ (n) = log₃ (k⁷) + log₃ (m⁶) - log₃ (n⁹)
logₓ(y) + logₓ(z) = logₓ(y * z)
log₃ (k⁷) + log₃ (m⁶) - log₃ (n⁹) = log₃ (k⁷ * m⁶) - log₃ (n⁹)
logₓ(y) - logₓ(z) = logₓ(y / z)
log₃ (k⁷ * m⁶) - log₃ (n⁹) = log₃ (k⁷ * m⁶ / n⁹)
Answer:
-11 x2 =-22 -2 =24
Step-by-step explanation:
Answer:
The father is 50 and his son is 15.
Step-by-step explanation:
Double the tens digit of the father's age = 10
Plus 5 = 15 (the age of the son)
50 + 15 = 65 (the sum of their ages)
The reverse of the digits of the son's age is 51.
Subtract 1 = 50 (the age of the father)
Answer:
(1/2)/(3/4) = (1/2)(4/3) = 2/3
Step-by-step explanation:
Answer:
( 5, 3/2 )
x = 5
y = 3/2
Step-by-step explanation:
5x - 4y = 19
x + 2y = 8
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2(x + 2y = 8) = 2x + 4y = 16
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5x - 4y = 19
2x + 4y = 16
7x = 35
÷7 ÷7
x = 5
-----------------------
x + 2y = 8
5 + 2y = 8
-5 -5
2y = 3
÷2 ÷2
y = ( 3/2 )
I hope this helps!
