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3 years ago

Expand the number 1120 into its corresponding exponential form. 25 · 5 · 7 52 · 8 22 · 53 · 7 2 · 5 · 7

Mathematics

1 answer:

Eduardwww [97]3 years ago

5 0

Answer:

(A) 2^{5} * 5 * 7

Step-by-step explanation:

Your question formatting made it very complicated to understand the possible answers. Please use some notation or the equation editor next time.

So, the exponential form a way to write a number using multiplications and powers.

Let's examine the various options (if I read them correctly)

(A) 2^{5} * 5 * 7 - YES!

2^{5} is 32, so 32 * 5 * 7 = 160 * 7 = 1120

(B) 5² · 8 - NO

= 25 * 8 = 200

(C) 2² * 5³ * 7 - NO

= 4 * 125 * 7 =500 * 7 = 3500

(D) 2 · 5 · 7 - NO

= 10 * 7 = 70

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Answer: 47/90

Step-by-step explanation:

3/10+2/9=47/90 somehow ig

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2 years ago

The shaded region in the graph represents the solutions of this system of linear inequalities:

kotegsom [21]

Answer:

$y$

$y\leq 2x+3$

Step-by-step explanation:

step 1

Find the equation of the solid line

From the graph take the points (0,3) and (4,11)

Find the slope

$m=(11-3)/(4-0)\\m=8/4=2$

The equation of the solid line in slope intercept form is equal to

$y=mx+b$

we have

$m=2$

$b=3$ ----> the y-intercept is the point (0,3)

substitute

$y=2x+3$

therefore

The inequality is

$y\leq 2x+3$

step 2

Find the equation of the dashed line

The slope is given

$m=4$

From the graph take the y-intercept (0,-5)

The equation of the solid line in slope intercept form is equal to

$y=mx+b$

we have

$m=4$

$b=-5$

substitute

$y=4x-5$

therefore

The inequality is

$y$

because the shaded region is below the dashed line

therefore

The system of inequalities is

$y$

$y\leq 2x+3$

8 0

3 years ago

Find the x- and y- intercepts of parabola y=5x^2-16x+10

____ [38]

Y-INTERCEPT

$y = 5x^2 - 16x + 10$

The y-intercept is where the equation/curve/parabola cosses the y-axis.

The y-axis is where x = 0. (The x-axis is where y = 0)

To find the y-intercept:

$\text{y-axis} \rightarrow \text{x = 0} \rightarrow y = 5(0)^2 -16(0) + 10 = 10$

The y-intercept must be at (0, 10)

X-INTERCEPT (ROOTS/SOLUTIONS)

$y = 5x^2 - 16x + 10\\\text{make it equal 0}\\y = 0\\\therefore 5x^2 - 16x + 10 = 0$

We need to use the quadratic formula

The quadratic formula helps us find what values of $x$ make the equation = 0

Quadratic formula: $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\frac{-(-16) + \sqrt{(-16)^2-4(5)(10)}}{2(5)}\\\\x = \frac{16 + \sqrt{256-200}}{10}\\x = \frac{16 + \sqrt{56}}{10}\\x = \frac{16 + 2\sqrt{14}}{10}\\x = \frac{8 + \sqrt{14}}{5}\\\\\\x=\frac{-(-16) - \sqrt{(-16)^2-4(5)(10)}}{2(5)}\\\text{doing the same thing...}\\\text{end up with...}\\x = \frac{8 - \sqrt{14}}{5}\\$