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3 years ago

Cos2x + sin2 x =______

1 answer:

8 0

Cos²(x) + sin²(x)
¹/₂[1 - cos(2x)] + ¹/₂[1 + cos(2x)]
[¹/₂ - ¹/₂cos(2x)] + [¹/₂ + ¹/₂cos(2x)]
¹/₂ + ¹/₂ - ¹/₂cos(2x) + ¹/₂cos(2x)
1

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Anastaziya [24]

Answer:

it's the first one because it is split as the paragraph said it should

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aleksklad [387]

Area= 3696in squared
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NNADVOKAT [17]

For this case we have that by definition, the equation of a line of the slope-intersection form is given by:

$y = mx + b$

Where:

m: It's the slope

b: It is the cut-off point with the y axis

By definition, if two lines are parallel then their slopes are equal.

Then, the requested line will have a slope equal to:

$m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {5 - (- 3)} {2 - (- 2)} = \frac {5 +3} {2 + 2} = \frac {8} {4} = 2$

Thus, the line is of the form:

$y = 2x + b$

We substitute point $(-4,5)$ and find "b":

$5 = 2 (-4) + b\\5 = -8 + b\\5 + 8 = b\\b = 13$

Finally, the equation is:

$y = 2x + 13$

Answer:

$y = 2x + 13$

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Gekata [30.6K]

5 3/10 because if it is in the tenth place it will be over 10 then 5 is the whole numbers. Did this help?

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Alexxx [7]

A = 143 m^2 because the height is 11 m and the width is 13 m if you add 9+4.

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